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x + Y
E:
•
(i)
Apply the
£
R
bas~c
Let x and f(O)
THEOREM. x
y.
He have the
R·, R·,
x E: R, y E: A and [x,yJ £ K => xy, yx E: (ih) x,y £ R and [x,y] £ K-> x + y £ R; {iv} x £ R (n > 1), x .... x in A and [x ,x] n n n
R.1.3
and
analogues of 0.3.6 and 0.3.7.
{li}
~.
x
£ K
(n > 1) => x
£
R.
properties of the spectral radius to elements in £
A
a
f
E:
HoI (O' (x) ) ,
....-:> f(x)
£
R;
and
A/K
then
53
(ii)
(iii)
R and
I':
(if
A is unita~)
cr(x)'-{o} -> f(x) Proof.
~s
(i)
xg(x)
cr(x + K)C:cr(x}
~ntegral
(iii)
x
f(x + K) = f(x) + K.
f(x}
I':
f
I':
f(x)
one
o => f(x)
f(O)
~mmed~ately ver~f~es
Hol(cr(x + K»
since
{oJ.
f(cr(x + K»
{oJ,
cr(x + K) =
so, by hypothesis,
i cr (x + K) •
cr(x + K),
cr (x + K) C cr (x),
How
hence
x
f
cr(f(x + K»
cr(f(x) + K»
character~sations
two
,
of the radical of a
characterisat~on involv~ng
lnv(A)
~s
un~tal
well known (BA.2.8)
involving the set of quas~n~lpotent elements We recall that if 1/I(k(h(K}» R.1. 4
THEOREM.
rad(A) = {x ~.1.5
1~
is the
rad(A/K)
=
I':
Let
Banach
COROLLARY.
54
wn~le
that
~s due to Zemanek (104).
A -+ A/K
then
A be a unital Banach algebra~ then
Let
A
£
A : x + Q(A)C:Q(A)}.
be unital then I':
A
x + RCRJ.
Riesz elements: spectral theory
Recall that if l(A}
I
K.
(BA.2.3).
x + Inv(A)C:lnv(A)} = {x
A
Q(A)
canon~cal quot~ent homomorph~sm
k(h(K» = {x e: A : x + ~K(A)C$K(A)} = {x R.2
does
so
algebra which lead to chardcterisaticns of the kernel of the hull of The
R.
£
therefore
~K(A) •
g~ve
Next we
then
cr(f(x + K»
K)
o 1. f(cr(x + K»
thus
R;
R,
£
K
not vanish on
Observing that
representation of
and
4> (A) => 0
I':
I':
does not vanish on
f
(~~),
f £ Hol(cr(x»,
cr(x + K)Ccr(x),
Now
and
and
f(x}
cr (f(x) +
cr(x)'-{o} => x
g £ Hol(cr(x».
x £ A
Since
x £ ~K(A)
a consequence of R.l.2
where
that if
f
~K(A) .
£
Using the Cauchy
(ii)
does not vanish on
f(x)
A
is a Banach algebra then
of inessential elements of
A
A' = A/rad(A)
is defined by
and the
~deal
(\ {p
I (A)
p r::J soc (A r) } •
€ Il(A)
We, henceforth, lnsist that
K
lS a closed inessentlal ideal of
that
A
and
lS closed ideal of
K
KC
I (A) •
carried out relative to this fixed ideal from
~K
K,
A, that is,
Our Riesz theory will be so we shall drop the subscript
~.
and
We are gOlng to deduce the spectral properties of Rlesz elements from the
A
Fredholm theory of Chapter F whereln i t is assumed that
lS unltal.
A
Thus, from R.2.l to R.2.6, when we use results from Chapter F,
wlll always
be unital and, at the end of the section, we shall show how these results may be extended to non-unltal algebras. R.2.l
DEFINITION.
A
plex number
Let
A
be a unltal Banach algebra.
lS called a Fpedholm point of
Fredholm or essential spectpum
A
w(x)
The Weyl spectpum of
W(x)
x
( \ CJ (x
of
x
In
A
x
If
If
A-
x € A,
x €~.
a com-
The
lS deflned to be the set
lS not a Fredholm pOlnt of
x}.
lS deflned to be the set
+ y) •
y€K The complex number invertlble, or If of
CJ
(x) .
A lS called a Riesz point of
A
lS a Fredholm pOlnt of
x
x
If either
A- x
lS
whlch is an lsolated point
The Riesz spectpum or Bpowdep essential spectpum of
x
in
A
lS
deflned to be the set
A
6 (x)
We note that
w(x),
lS not a Riesz pOlnt of
W(x)
and
Sex)
x}.
are all compact subsets of
~
anu
the incluslon
55
w{x)C. W(x)C 13 (x)C a (x) ,
is valid for
W{x)
Let
THEOREM.
A
Tak~ng
u
The
Clearly,
~t
follows that
inclus~on
Sex)
whenever
~s
X
K
is proper,
w{x}CW(x). ~s
W(x) 2).
it follows,from (BA.4.5), that
{ak}~'
p (H)
Then
O(f}=O(f n
Relatlve to the decomposltion
n-
H =
s
n
l)V{aJ,
(H)
n
ED
(1-5
n
)tw
we have
where
h
n
x j (1 - SI: ) (H) •
n
By (BA.4.5),
a(x + y ) n
Now if
A S a(x + Yn ) for each n, hence, Slnce A S o(x + y} . It follows that 0 (x)"w Co (x + y) •
A S a(x),w,
is open in
A,
then
To prove the reverse inclusion, suppose that A S p{x)uw,
n':::' m, 74
so we can choose
m > 1
such that
A ¢ o(x)'w,
Inv(A)
then
A ¢ O(x),,{\}~.
Then, for
h
=
n
h
m
I (l - s
n
) (H),
"lhere the inverses
ex~st
the decomposition
H =
W
Then
:1 -
Also
h
Ilwnll.2 llwmll
Now, s~nce
n
by virtue of the
n
CH}
s
(1 -
$
n
)
cho~ce
(H) ,
(A - h ) -11 (1 - s
m
of
m.
n
) (H)
I
Then, relative to
'Trite
~ )-~
(A
n
s
0. - h )-1
and so
n
for
n > m.
Fix
n > m
! lY
so that
l
- Yn !.::.llwmll:l
(Y - Y ) Is (H) = 0, n n
:J
[:
~
(A - x -
-1
y)
n
hence
W
n
[(A:
(y - Yn )
[:
y ) n
(y
(A _Ohn ) -l z
f )-1 n
(A : h ) -lJ [: n
J.
:]~ u-: )1']· n
Now,by (BA.4.5),
r{
(A -
Therefore
x - Yn )
1 -
(A -
-1
r{ W (Y - Y )}
(Y - Yn ) }
n
n'
correspond1ng to the spectral set
I \1 ~ €2}. Then p E H(A), and p commutes wlth x*x, I I (x - xp) * (x - xp) II = II x*x - px*x II r(x*x - px*x)
- ex*xe)e
def~ne
E
y*x.
ey*xe
second.
so
= e*
by
<x, y>e
thus
e
(If
e
I
H) e
is a *-representation of
A
79
TI e
(i)
(span AeA)
ker TI e e (BA.3.5).
p
(iii)
Proof.
the unique ppimitive ideal of A which does not contain
e
def~nition
It follows at once from the on
A
H : e
e
TI (A)::::> K (H ); e e
(ii)
of
F(H );
He'
If
z + y (z E H ). e
TIe
a
~s
*-representat~on
denote the rank-one operator on
x III Y
Then
yex*ze
yx*z
TI (yx*)z e
let
x, Y E He'
that
(x III y)z,
y
Now every element of AeA is of the form yx* where TI (yx*) = x III y. e From this we conclude that 'IT ~s irreducible x, Y E He' hence (i) follows. e thus
on
H thus ker(TI) e e ker('IT ) = p .
e
pri~tive
is a
of
A
and
e ¢ ker(TI ), e
s~nce
e
(ii) follows from
(~)
•
s~nce
because,
B(H ) (BA.4.1) e In our main theorem
and
Let
THEOREM.
A
TI
(A)
Fredholm elements of a C*-algebra C*.4.3
~deal
~s
e
TI
e
(A)
~s
closed
will denote the set of Riesz and
relative to the closure of the socle.
A
be a C*-algebra.
thepefope isometnc) peppesentatian
cont~nuous,
(TI, H)
'lhepe exists a fCJ:':thful *-(and of A with the following
properties: (i)
'IT(soc(A})
(ii)
TI(soc(A) )
F(R)
n 'IT (A) ;
K(H)n
TI(A);
(iii)
'IT(R(A»
R (H) fI TI (A) ;
(iv)
'If((A»
(H) fI TI (A)
Proof.
Let
A
not contain
1\
of
80
be a set which
soc (A) •
p~
if
= A
p
,
eA on
A
i8 unital.
~ndexes
20r each
A E A,
the
pr~~t~ve ~deals
we can choose
eA=
and then, by C*.4.2, there exists a Define
of
A
e~ £
wluch do Min(A)
*-representat~on
~n
Then
~s
TIl
a *-representation of
on the
A
H~lbert
HI'
space
Now
tl ker(TI ) = f1 {p € TI(A) PA::j> soC(A!, by C*.4.2. As A€A A A€h A have a non-zero kernel ~t is necessary to add another representation
ker TI
=
1
order to ensure that the sum
TI
be
fa~th:ful.
theorem «14) 38.10) on the C*-a1gebra
Use the
A/soc (A)
then
representat~on
=
ker(TI)
Now ~f
TIl (x) € F(H I )· A
such that
therefore
'If
~s
and s~nce
TI
so
TI
fa~thful
is a
'If
'If \ (x) € F(H A), ~t follows that
12
2 n},
j
TIl (x) € F(H l ). But ro verify (~), observe that
TI(soc(A»C F(H) •
cs an ~dea1 of algebraic elements of
F(H){\ TI(Al in
soc (A)
*-representat~on
B (H),
closed ~n
(~).
~t ~s
hence
F (H) ()
so
obta~n equal~ty
let
and
p2
=
p*
~
~
~
iT
T = T* € K(H){) 'If(Al, € K(H)~ 'If (A)
is of fin~te rank, so operator
isometr~c
«75) 4.8.6), and
(Al C'If (soc (A) ) c K (H) () 'If (A) • T
LAP.
~
1
~
A.
where
~
S = TI + ~T2
where
TI' T2
are
TI(soc(lGI)~K(H)A 'If(A),
(~~).
The proofs of (~~~) and (~vl are now stIa~ghtforward (see A.I.3) C*.S
€ ffi,
S~nce every
T € F(H){) 'If(A).
~t follows that
K(H){) TI(Al,
~
To
But each compac~ proJect~on
i.
thus
may be written
self-adJo~nt members of Whence we have equallty
then
for each
Pc € F(H)O TI(A),
S C K(H){) 'If(Al
A,
(C*.4.1), therefore
\lhence we have equah ty
(A),
{Al",An }
so
00
P
*-
hence if
there ex~sts a £in~te subset
x € soc(A),
conta~ned
fa~thfu1
cs a
'If (soc (A) )
~n
to construct a *-represen-
for
= 0,
therefore
the ~nverse ~mage of 'If (soc (Al ) ::> F (H) n
'If •
x € span {AeJA :
ker('lf 2 ) = soc (A) , \m~ch ~s
'If~(x)
then
€ span (AeAA) ,
of
(0),
TI2
•
Let us examine the range of X
=
ker TIl{)ker TI2
may
Ge1fand-Na~mark
Put
HI ED H2 ,
'IT1
tt
Notes
Very neat proofs of the range H~lbert
space
H
C*.5.1
LEMMA.
follow~ng
Vla the
(The footnote In (28) S, T €
~ncluslon
announc~ng a~
B(H),
theorems of §0.4 can be
factor~sat~on
g~ven ~n
a
Lemma due to Douglas (28).
extension to Banach spaces is
S(H)CT(H) => there exists
C € B(H)
~ncorrect).
such that
S = TC.
Proof.
SJ..nce
y € ker(T)l.
S (H)C T
such that
(H)
I
then for each
Sx = Ty.
Put
Cx
X €
y.
H
there
ex~sts
C
lJ..near and we prove C
J..S
a unique
81
Let
is co~tinuous by means of the closed graph theorem « 30) p. 5 7) • be a sequence in
H
ker(T).L.
since
=
SU
Tv,
C*.S.2
~s
LEMMA.
=
thus the graph of
v,
S, T E B(H},
S
By induction
n
n n
T C
=
and s
TS
ST
C
S E B (H)
COROLLARY.
Proof.
Apply C*.S.l
C*.S.4
COROLLARY.
Proof.
Apply C*.S.l and C*.S.2
C*.S.S
COROLLARY.
S E
~.
R (H)
•
S E B(H),
S E B (H)
S = TC
by C*.S.l.
=
0
Let Then
1/!
S(H) 8 E Q(H).
ST - TS E K(H)
be the canonical
1jf.S}
hence, by C*.S.2,
Erdos (31) defined an element 0 => either
ax
=
0
or
I
1/! (T)
and
S(H}C.T(H}
r(ljJ (8»
xb
=
Erdos pOlnts out that
simple Banach algebras. prove that an element
The
of a
semis~mple
rank one operator in some faithful single and the operator
h~s
In fact, In (32) x
x 1\ x
0, that ~s
of an algebra
~s
A
s~ngle
to be
slm~lar
single
elements of use of
•
Banach algebra.
th~s
~f
B(X)
are
concept Erdos
to that in §4, see also
work does not extend even to semlI
Erdos,
G~otopoulos
and Lambrou
Banach algebra has an image as a
r~presentat~on
compact.
B (H)
of
8 E R(B)
sem~simple
a
Mak~ng
constructs a representation of a C*-algebra Ylinen (100).
=
x
O.
homomorph~sm
commute and 1/! (S) = $ (T}lj! (C) •
~s val~d ~n
C*.1.2
easily seen to be the rank one operators.
82
K(H}.
•
r(ljJ (T»
=
•
T E R(H) ,
I
and
TS
ST
T E Q(H),
Alexander (4) showed that
axb
S (H)C T(H) => S E
•
into the Calkin algebra. Now
I
•
II sn II 2. I ITn II I Ic n II ,
thus
and
T E K (B)
C*.S.3
So
TC => reS) < r(T}r(C).
=
n,
for each
closed
~s
and the result follows from the spectral radius formula
='>
and,
such that Sxn = Tyn for each n, Yn E ker(T) J.. a closed subspace of H, lAm Yn = v E ker(T}
Cu
hence
v.
lim Cx n n
.....
Then there exists
n
such that
u,
lim x n n
{x}
The
of the algebra x representat~on
is
in §4 may be
used to transfer Lnformation on finite-rank, compact or Riesz operators on Hilbert space to finite-rank, compact or Riesz elements of C*-algebras.
It
could, for example, be used to deduce the West and Stampfli decompositions in C*-algebras (C*.2.5, C*.2.6) from their counterpart theorems for operators (C*.2.1, c*.2.2).
Legg (58) has gLven the C*-algebra counter part of the
Chui, Smith and Ward result (26) that the commutator Ln the West decompoSL tion is quasLnilpotent.
In fact, the more de taL led informatLon on the
West decomposition provided by Murphy and West (61), (see below),is all valLd LIl a C*-algebra.
Akemalln and WrLght (3) have further results on the wedge
operator, and on the left and rLght regular representations in a C*-algebra. For example, they show that Lf operator either GLllespie «35),
S
or
S, T £ B (H)
T £ K(H).
then
R
R = K + Q
[K,
R
on a HLlbert
Lnto the sum of a compact plus
a quasLnLlpotent dLd these two operators commute.
then the commutator
is a weakly compact
(25) p.58) constructed a Riesz operator
space such that for no decomposLtLon of
showed that if
S AT
See also the rema~ks in §F.4.
Chui, Smith and Ward (26)
LS a West decomposition of a Riesz operator
Q]
LS quasinLlpotent.
R
Murphy and West (61) gave
a complete structure theory for the closed subalgebra (called the decornpo-
sition algebra) generated by
K
and
Q.
It emerges that the set of quasi-
nilpotents forms an Ldeal which LS equal to the radLcal, and that the algebra LS the spatLal dLrect sum of the radical plus the closed subalgebra generated
K.
by
The problem of decomposing Riesz operators on Banach spaces has been open it may even characterLse HLlbert spaces up to isomorphism.
for some time.
Some recent progress LS due to RadJavL and LaurLe (73) who showed that if is a RLesz operator on a Banach space and
0 (R) =O\n}~
I
values are repeated accordLng to algebraLc multiplLcLty(then decomposition Lf
f nlAn'
relative to
(Al f\ B ~(T)
a necessary condJ..tion 1f
J..S semJ..sJ..mple.
:.\.1.1 THEOREM. (T £ B).
Proof. then in
£
qJ (A) r) B
qJ (B) •
=
T
in
B.
EXAMPLE.
ix(T) -I- O. T
£
qJ (B) ,
Take
Let
T; then
where
relatJ..ve
=
WA(T)
for each
T
E:
FJ..rst we gJ..ve
B.
then a
Inv{A)nBCInv(B).
If
T
£
B
(J (T) A
=
(T)
Inv(A) () B,
Now the left and rJ..ght annJ..hJ..lator ideals of
T
By F.l.lO,the left and rJ..ght Barnes lde:.mpotents of T In
B are both zero. hence
ing
B
are zero, hence the same is true of the left and rJ..ght annJ..hilator
ideals of
A.1.2
J..n
be semisi7Tlf?le.
B
It suffJ..ces to show that T
A
Let
qJ(B)
and
but the converse does not hold J..n general.
If we do have equality then B
KA ,
B
aB (S)
1B (T)
0
A
E:
Inv (B)
•
KA = K(X) and choose T £ qJ (X) wJ..th be the maxJ..mal commutative subalgebra of B(X) contaln=
B{X},
(JA (S)
(S £
sJ..nce
B
B)
(BA.1.4) , but
T ¢ qJ (B) •
and
For, If
J..s commutatJ..ve, and we can wrJ..te
KB , by F.3 • 11, J..mplYJ..ng that T Fredholm operators of J..ndex zero J..n reX}) whJ..ch is false. V E
Inv(B)
=
T
K £
of Theorem A.l.l J..S not suffJ..cJ..ent
£
T
qJ0 (X)
V
+
K
(the
So the condJ.. hon
for general B.
For C*-algebras we do get equalJ..ty. A.I.3
THEOREM.
ct>(B) = qJ(A) (\ B. Proof.
The map
Let
A
be a C"'-algebra and
B
a *-subalgebra of
A;
then
~(B/KB)
is a *-lsomorphism so Thus if
~(A)~B,
T E
hence, in
W(B/KB )
is a *-closed subalgebra of
~(T +~)
then
(BA.4.2).
A.l.4
THEOREM.
Proof.
If
A
and
=
R(B)
B,
It follows from R.2.S that A.l.S
B
THEOREM.
Let
0 ~ :>..
T E R(B)
B~KA'
.
Now
2hen T = K + Q ~here K nilpotent operator in B.
by deflnition
is countable, hence
then
0 ~ P(A,T) E KBC KA •
be a Ries2 operator on a Hilbert space
T
T E ~(B) . .
= GA(T).
T E R(A)
\ P = Q,
1
~nd
T
TT*,
A
A,
wA (T)
then
to be pr1m1tive.
Let
T S l).
(L
then
> 1),
(i
If
> 1).
then
(J ~ 1),
= 0
l=l L LJ
A.4.2
,,0
t
00
is a sequence
denotes the closed sub-
T(X)
is invertible.
T
a S X',
then
00
o
Thus
n
al
~
(L
= 0
If, in additlon,
o
= lX(T),
A.4.3
a
so
t
(n
L Ln
> 1).
1), by A.4.1, hence
T S ¢o(X) niT)
= 0,
then
a = 0,
T(X) = T(X} = X
hence, by F.2.8,
o
LEMMA.
T
for at
T(X)
and
so
d(T} = O.
But
tt
LS LnvertLble ~ost
X.
lS dense in
a finite number of indices
i. Proof.
Suppose that the set
such that
S S B(x)
and
h
W
!I S II
:
t
l
= O}
lS LnfLnite.
< £ => T + S £ ¢o (X) •
Choose
'rake
S
£ > 0
to be the
.J
operator corresponding to the dlagonal matrlx [s where s .. = 0 J) , (L " lJ LJ -1 (l ¢ W) = El Then S £ B and and s (L E W) • < £, sa = 0 lL thus Tl = T + S E B 1\
0.
B
1 (R
=
+ M)
V E Inv{to),
T to - M
=
and
V E Inv{B)
f'\ ¢o (X)C ip0 (B)
A.4.S
ip{B)
then
f{T) E B,
=9
for
(R.S.2)
A.S If
Kto ,
toCB.
By A.4.2,
thus
1 (T)
So
R(X)
to. to)
If we put
R to E
¢(B)
R{X) = X. S
and
Hence
glves
Thus we have
= O.
is an upper triangular operator on
T
W (f{T»
f(W(T»
X
and
• by A.4.4.
Also
and the result follows from the spectral mapplng theorem
•
H
P
is a Hilbert space let ordered by
B~H)
2
P
Q
if
denote the set of hermltean projectlons In QP =- P
PQ
( P(H)CQ{H»
Note that
F
~
LEMMA.
~.
is not an algebra.
B(H)
Q
E
T
E
~(\
{H) => lH(T)
~
F(H)
such that
such that
peT + F) = Let
T + F
o. Q
?ut £
and
P.
R
KA
These
K (H)C ~ K(H) •
O. lH(T) < O.
By F.3.1l ,
has a left inverse
P with
~.
lS denoted by
A = B(H)
Let
Suppose, on the contrary, that £
P,
0,
operators were first studied by Halmos (39) who showed that
A.S.I
for
is quasi triangular If
and the set of quasitriangular operators In
Q.4
= K(x)~
by F.3.11.
The same argument applled to
O.
lim lnf IlpTP - TPII P
an
Kto
Algebras of quasltrlangular operators
F{H) T £
M E
Slnce
(T E B), T £ B
KB
E
•
If
COROLLARY.
f e Hol(a(T»
>
1 (R)
l{S)=-l(T),
But
K, L
denotes the index function In the algebra
all its diagonal entrles are non-zero. 1 (T)
and
TtoS to = I + r,to' lS a Fredholm element of the commutatlve Banach algebra
Tto
of all diagonal operators on
Hence
S E B
Hence
T + F, Q > p;
then then
S, R
E
there eXlsts
and aPE p,
Q6'
PQRQ = 0,
since and since
0
i P
~s f~n~te ~mensional
QB{H)Q
QRQQo = O.
such that that
P (QRQ) = O. s~nce
and,
there~n.
~s
QRQ
So
II RQ
II RQ -
QRQ
I)
2:..
II ·11 Qo II
II s
A = B{H},
C*-subalgebra of
dimensional,
QRQ
Qo £ QB (H) Q
~s
I ! -1
> I! s (RQ - QRQ) Q
0
(for
Q
P
£
T £ B
~
K(H)
KA =
(T, T
-1
and let
£ B(H)
has the property that
at the zero ~deal
B
such algebras
such that
Pn
{o},
-+
I
where
H
and
B
£
H,
! IP n (x
and
Now
1.
be any
T
Q
2:..
contradicting
P),
un~ta1
B => T
£
o
({a})
be separable and
B
Define
lipn T
-
Routine computatlon shows that
x, y
QRQQo = 0,
II
such that
tB (T) (P)
lB(T)
strongly.
{T £ B(H)
B
QB(H)Q,
-1
for
inverse-closed
B)
£
which contains
B, the index function
P £ IT (B) except perhaps F~rst
iH(T) •
let us see that
ex~st.
Let
EXAMPLE.
A.5.2
and
not right invertible
such that
Note that in such an algebra of
0
P £ QB(H)Q,
R £ ~ •
the fact that Now let
t
0
Q < Q
P,
£
to be a projection which is therefore < Q) •
Qo
- QRQ
Q o
not left invertible in the algebra
fin~te
this algebra is
lIs II-
there eXlsts a
(To verify this observe that
So there is a non-zero
we can choose
Thus
{C*.1.2},
TP
B
n
II
-+ 0
f~x
an
~ncreasing
sequence
P
n
P
£
by
(n -+ (0) }.
lS a closed *-subalgebra of
B (H) •
Let
then
GIl y)
-
(x ill y) p
n
II
(P x) GIl
n
0
such
1
L (G)
w~th
with respect
proof.
Since
MO
T(G) = span{MeJ If
]1
form of
a
M(G),
E:
]1.
~(a)
let
Let
e*Xa
e
T (G) .
E:
I
L (G)
Thus algebra.
(x E: L
A.6.2
I
Hence
¢(M(G»)
Let
LEMMA.
jl
S
Suppose
eJ, hence
o
"1(G)
a
then there exists
I
0
2: (G)
E:
such that
«45) 28.39), thus
soc(M(G»CTcG)
lS a closed ideal of
S
M{G)
deflne
Tjl
E:
M(G)
a(T )
1.1
I
0
which lS a Rlesz
B(LI(G))
be the ldentity measure on
=>
e*Xa
•
M(G)
denote the set of Fredholm elements In
If]1
0
be a flxed Fourler-Stlelt]es trans-
(e*v )' (0) AO
It follows that
(G».
Proof.
L: (G»
Mln(M(G»,
E:
Ll(G).
relatlve to
(0 E:
= soc(M(G»
Let
for each
SOC(M(G»
L:(G)}Csoc(M(G».
E:
((45) 28.36). and
~E:
lS flnlte dlmensional,
by
M(G).
= a(jl).
1
E: Inv(B(L (G»), then there eXlsts such jl 1 that T S = T", = ST. If x, Y S L (G), then T «Sx)*y) = jl*(Sx)*y jl Uo jl 1.1 1 = (TjlSX)*y = x*y = T (S(x*y». Thus (SX) *y = S(x*y) (x,y E: L (G) >':'1 By Wendel's Theorem ((4g) 35.5), S = Tv' .Eor some \! c M(G), thus \! = jl in M(G),
A.6.3
T
I
THEOREM.
I
has finite co-dimension in
jl*L (G)
L (G)
T
]1
is a
Riesz-Schauder operator. I
Proof.
I
I
]1*L (G) = T (L (G» hence, by (25) 3.2.5, Slnce ]1*L (G) ]1 co-dlmenslon It lS closed in LI(G). Suppose that {Ol"'" a~}
of dlstlnct elements of
(1 < k < m).
If
L:(G),
and that there exist
AIY l + ••• + AmYm = 0
where
~
S
Ma'
Yk
S
~
(1
A.6.4 Lmplies that Lf ((25) 1.4.5)
4t
=
W(fj)
AO
o
-
W()..l)
=
If
=> (i).
)..l E ¢o (M(G)}
then, by F. 3 .11,
+ K E Inv(M(G»,
LS a factor~sation of E ~HG)
\.l*K = K*~;
¢ = ¢2 E: T(G) •
are idempotents in soc(M(G)} = T(G)
COROLLARY.
Proof.
(~~i)
Conversely, if
K E ¢1*M(G)*¢2
)..l = (00 - $l)*(\.l + K) A.6.5
and
=>
(~v)
and
K E: T(G)
Inv(M(G»
\! £
by A.6.3,and
Obviously (v) => (ni) •
of
Inv(M(G»,
E:
\.l*¢l
(A.6.ll.
)..l
=0 =
¢2*1J,
Now
4t
as Ln (v)
S()..l).
11 E: C
If there exists a maximal modular left ldeal
L
of
A
such that
{x £ A : xAeL}.
BA.2.1
(i)
A is ObV10US, so assume that there exist (BA.2.2),
y so
E A,
x
Z E
rad(A)
x'
such that
has a left inverse in
(iii) follows at once
has a left lnverse in yx = 1 + z.
But
A'. 1 +
{x
£
£
Inv(A)
• A.
Let
P E
there eXLsts a maximal modular (and therefore closed) left ldeal p
z
A.
Now specialise to the case of a Banach algebra such that
Then
A : xA C.L} •
It follows that
P
1S
11(A) L
closed in
then of
A
A. 103
Further, by BA.2.l,
P
is the kernel of the
representation on the quotient space th~s representat~on
the image of operators on
AIL,
Thus,
~t w~ll
A'
A
=
~s
erA' (x')
primitive
If
BA.2.6
algebras
B(A/L) ,
Now
the bounded linear
suff~c~ent
of
to consider the
rad(A)
algebra
A
cont~nuous irreduc~ble
is a closed
~deal
of
A,
and
It follows from BA.2.5 that
Banach algebra.
~n
deal~ng w~th
X.
for Banach spaces
A).
S
loss of generality, uhen
\l~thout
se~simple
a (x
~deal
~n
is contained
is a Banach algebra, then
= A/rad(A)
erA (x)
be
B(X)
representations into If
is a Banach space.
hence,by Johnson's theorem «14) 25.7), this represen-
tation is continuous. Banach algebras
wh~ch
AIL
left regular
~rreduc~ble
py.i~tive ~f
is
~s
zero
a
A.
is a Banach algebra and P s TI(A) the primitive Banach and A'/p' are isometrically isomorphic under the map
A
Alp
x+P-+x' +P'. Proof.
The map
~s
~somorphism s~nce
an
rad(A)C:P
(P S
TICA».
A
straightforward computation shows that the mapp~ng ~s an ~sometry
closed subalgebra Proof.
B
P -+ P(\B rad(B)
=
eAe
is a
eAe
~s
closed
B =
Banach algebra and e 2
(0)
~n
A of
since
BA.2.8
Let
(i)
rad(A)
~
e
TI (A)"'h (B)
then the
~s
~dempotent.
onto
IICB)
The map
((14) 26.14), so
..
quasin~lpotent character~sation
due to Zemanek (104).
e C A,
is sewisimp le .
homeomorph~sm
rad(A) f\
The
se~isimple
If A is a
BA.2.7
..
Q(A)
of the
ra~cal
in the next theorem
~s
denotes the set of quas~n~lpotent elemenrs of A.
be a unital Banach algebra, then contains any right or left ideal al! of whose elenents are
quasini lpoten t; (ii)
rad(A)
(iii)
rad(A)
~.
(ii),
{x s A
x + Q(A)CQ(A)}; x + Inv (A) C Inv (A) } •
(i) follows from (14) 24.18. (iii)
We show that
x + Q(A)CQ(A) => x S rad(A) => x + Inv(A)C.lnv(A) ==> x + QCA)CQ(A).
x + ~(A)c:Q(A) .
Let
~rreducible
representation of
~ E X
Choose
there exists
u E A
o 1 A E p(u}
and put
-1
rr(v rr(v rr(v
-1
-1
-1
x - v
x
-1
xv E Q(A)
E P
)rr(xv
Inv(A).
E
If
Thus
u
x E
BA.3
MLn~mal
Let
A
~deal
in
~deals
~
J
minimal
n(u)rr(x}~ =
~.
Choose
Q (A) => v
-1
xv c Q (A) ,
hence
contra~ct~on.
is a
It follows that
(Ll
+ x)-l
u
-1
(1 + xu
-1 -1
)
,
hence
CA
AX + Inv(A)C- Inv(A)
q + x E
Q (A),
«::)!
E
1 + A(q + x}
Thus
(A E x E Q.(A).
Then
a
(0)
and
ide~otent ~s
is a dLvlsion algebra.
(If
of mlnimal Ldempotents in
A
~~nimal
A
J
right ideal of
are the only
a non-zero
lS denoted by
r~ght
~dempotent
lS a Banach algebra Mln(A).
A
e
is a rLght
Ldeals contaLned such that
eAe =
~e)
•
eAe
The set
There are sLmilar
statements for left ldeals. BA.3.1
If
A
"is a semis?:mp le algebl'a, then
CLl
R-
is a min'imal right 1:deal of A
(il)
L
is a '7Iinimal left ideal of
(ui)
(l -
e}A, (A(l - f»
30.6, 30.11).
A L
eA
where
Af where
e
E
Min (A) ;
f s Min (A) ;
1.-8 a m=imal modulm' right (left) ideal of A
if, and only if, e, f S Mln(A) • ((14)
R
be a minimal right ideal 0-1' A and let u E A. 'lhen " either uJ = (0) , or uJ is a minimal right ideal of A. is a minimal right (H) If x E A , e E Mln(A) and xe of- 0 then xeA ideal of A. (l)
BA.3.2
«14) 30.7, If
A
Let
J
(75) 2.1.8).
has minlmal rlght ldeals the smallest rlght ldeal contalnlng them
all is called the
right socle of
A.
If
A
has both mlnlmal rlght and left
ideals, and if the rlght and left socles of
socle of A eXlsts and denote It by exists, is a non-zero ldeal of ideals we put BA.3 • 3 (l) (H)
Let
A.
A
Clearly the socle, If It
soc (A) . If
A
are equal, 'Ie say that the
has no mlnlmal left or rlght
soc (A) = (0).
be a semisimp le algebra 1Ji th idea l soc(A), soc (J) exist; A
Then
J.
Min (J) = J (\ Mln (A) ;
(Hi)
soc(J)
=
Jf\SOC(A);
if A is a Banach algebra and
(iv) Proof. (ii)
then
e, f E Mln(A)
dlm(eAf) < 1.
«14) 30.10, 24.20).
(i)
straightforward.
(iii)
follows from (li) and BA.3.1.
(iv)
«14) 31.6).
Let A be a semisimple algebra, P E canonical quotient homomorphism ¢ : A -+- AjP. BA.3.4
~nd
TI(A),
Then
let
.""l.jP
¢ denote the is semisimp le and
¢(soc(A) )C.sOC(¢(A). Proof.
¢(Min(A»C-Min(¢(A»)
and the result follows from BA.3.1
tt
The relationshlp between mlnlma1 ldempotents and prlmltlve ldeals is important. BA.3.5
Let A be a semisimple algebra. there exists a unique P e E II (A) If e £ Mln{A) 2 If e = e E soc (A) I the set {p E II (Al : e ¢ p} 1
Proof. (BA.3.l) Clearly 106
(il
If
e
E
Min(A)
therefore
1
e
¢
Pe'
P
If
e
'"
{x
then
A(l - el
E A
xACA(l - el}
Q E TI{A)
and
e ¢ Q,
such that e ¢ Pe' is finite.
is a maxlmal modular left ideal
then
lS a prlmitlve ldeal. Q f\Ae =
(O),
Slnce
Ae
is a minlmal left ideal. qAe = (0).
Thus
It follows that
Qe = (0). ~
q
P C Q,
e
(il) (1
C*-algebras
that
then
A
then there exists
a singleton set for each
A Banach algebra
The
E
hence
contains two distinct points.
(x)
BA.4
hence
oJ Y
0
(y E A), hypothes~s
yx, xy E Inv(A) ,
Thus, by (14) 24.16,
•
:'Iow, i f
Thus
r(xy) = 0 then by the
If A is a semisimple Banach algebra and if p
BA.3.10
o
r(xy) > 0,
is not zero.
= o.
x
such that
contrad~ct~on
r (y - Al) = 0
so
0
yEA
0(xy) = 0(yx) which is a
f
Then we claim that
rex) = O.
for suppose there exists and (14) 5.3,
A = ~l.
then
x E A,
is a
0(x)
A
and A/I
in the
into a C*-aZgebra
B
Let
BA.4.2
be a unital C*-algebra and let
A
$ubalgebra of A
then
GB(x) = crA(x)
B
be a closed unital *-
(x E B).
( ( 75) 4.8.2).
Let
BA.4.3
If
(i)
and
be a C*-algebra.
A
f
there exists
f2 E A,
e
= e2
e* E A
such that
fe
=e
ef = f.
If
(n)
such that
contains a right ideal
A
there exists Proof.
there eX";'sts
e = e* E Min(A)
R = eA.
If
(ill)
is a rtrinima3 right 1:deal of A,
F
(1)
e = e
2
~
= e*
R e f f A (fl' E Min (A) , 1 < i < n) 1
1
ouch that
soc (A)
R = eA.
USlng the Gelfand-Nalmark representation this
the elementary assertlon that If a H~lbert
operators on a
proJect~on
is contalned
~s
eqUlvalent to
~n
a C*-algebra of
self-adjo~nt
space then the C*-algebra contains a
proJection Wlth the same range «84) 6.1). If
Then
R
lS a mlnlmal rlght ldeal there eXlsts £2 = f E Min(A) 2 By (1) flnd e = e e* E A such that fe = e, ef fA.
R
fA = efACeA
(lli)
such
R
feA c. fA.
Slmilar argument
Thus
R = eA I hence
e
E
f.
fun (A) •
..
It lS elementary to check: the unlqueness of the self-adjoint idempotents in BA.4.3.
BA.4.4
Let
(1)
soc(A)
Slnce a
C*-~lgebra
be a C*-algebra, then
A
=
(soc(A»*;
x E soc (A) x*x
(ii)
socCA);
E
x E socCA) x*x s soc (A) •
(li1) ~.
(1)
If
x S soC(A) ,
then x E
and each fiEMin(A}.By BA.4.3,
x = ex, (ii)
lS semls1mple lts socle eXlsts.
hence
x*
x*e
=> is clear.
there eX1sts
e
=e
x*x(1 - e) = 0, Ilx - xel1 2
Let 2
=
R = eA
RC~f.A 1 1 where
where R is a right ideal of A 2 = e* E soc (A) • So
e = e
AeCsoc(A).
E
x
S
A
and suppose that
e* E soc (A)
such that
x*x
E
socCA).
Then
x*x E Ae (BA.4.3).
Thus
and
II x
(1 -
e)
112
11(1 - e)x*x(l - e)11
0,
109
so
x = xe
(iii) A/I
soc (A) •
£
Let
I
be a closed ideal of the C*-algebra
A.
Then
I
I*
and
is a C*-algebra (BA.4.l), hence II (x* + I)
Ilx*x + I II
so x*x
£ I
I
X £
(x
+
I)
I~
IIx
+
III 2 .
•
Finally we need a result on the spectrum of an operator matrix.
Q, and
denotes the interior of the set
If
BA.4.5
T
int(a{U)n a{v»
D
=
o
a (T) = a (U) u
then
= ~
intW)
U, V E B{H) •
and
* V
0 (V) •
This follows immediately from the following lemma. BA.4.6
(a(u) va(V) )'dnt{o{O)" a(V»C a(T)Ca(U) v o{V) •
Proof.
Elementary matrix computation shows that (a (U)
u a (V) )' (o (U)" a (V) ) C
Now choose
A
E
a (a {O}"
0
(V) )
a (T) C.a (U) va (V) •
then
A
E
aa (U)
A - V is a two-sided topological diviSOr all bounded linear operators. IIAnll
=1
for each
(l-T)
So
each
l~O
B
n
e~ ther
In the first case there exist
A -
U
A
n
with
(A - U)A + O. n
D (A - V) ..... 0,
so
U)A
n
o .....
o
hence
or
of zero in the Banach algebra of
In the other case, there e~st
A E aCT) • n, and
n, and
ao (V)
\J
Bn
with
0,
IIBnl1
I
for
D
o
o
+
o
B
n
AE
again
a(T) •
o
o (A-T)
B
n
C\ -
0,
V)
d (a (U) () a (V) )C a (T) •
Thus
It is easy to see that the result of BA.4.S fails if we drop the condition that
int(a(U) tl a(V}) =