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p ~ m 2. mI = ~ kI E
~ k 2 = m 2.
p is m i n i m a l ,
p C ~ and
p A kI
p ~ m I.
Proof: 1.1.1.
Consider
the
case
p A k 2. N o w
p ~ m 2 by
the
above
s.c.,
hence
P ~ m I• 1.1.2.
1.2.
1.3.
In t h e
ease
p E k 2 we
hence
p ~ mI.
Since
K I = Pl
there
exists
We
assert:
Proof:
and
the
infer
s.c.
a substitution
from
p A k I that
is p r o v e d
p = ~p A ~ k I = m I,
for minimal
(~,k1,~1,~,~,mT).
8k 2 = ek2 (= m 2 ) .
We write
M(k2)
= M ( k I)
~ R and
conclude
p
(see
(2220)),
34
M(~k 2) = M(m I) ~ R = M(Sk2) Further, i,i'
pos(~,m)
1.2.
= pos(llm)
£ ~1" The latter
by definition By virtue
of
since ~m 6 R, am = Bm = m.
implies
(2210) (2216)
and pos(~,ml)
(iv). By
V n 6 M(ml) , pos(l,n) (2212),
there exists
(T,k2,~2,B,l,m2) , which 2.
~2 ~ C(122,n 2)
I--
,6 "~ D ~
C(122,k2) ~
f_
!
~T
IT
%
C (121, k2) C--~. C (121 ,n I )
(The a r r o w ~ uniquely
- denotes
the i n c l u s i o n
f
determined
embedding.)
by this p r o p e r t y
and thus
a,
are
6, Y are ~-isomor-
phisms.
(iii)
Let
~
= ~ 0 ~ 0 ~, def
pos(111,n1).
Then
ak I = k I and k I & n 2. follows
from the i m p l i c a t i o n s :
k I = ak I 6 C(112,n2) k I & n 2 or k I ~ n 2 ~k I = k I ~ n 2 = ~n I => k I ~ nl,
in c o n t r a d i c t i o n
to
kI A nI. 1.1.
1.1.1.
We assume
m 6 C(111,ki)
and will
Clearly,
am 6 C(112).
Consider
the case m ~ k I. H e n c e
showam
6 C(112,ki).
am ~ ~k I = k I and
86
a m 1.1.2.
In
6 C(112,ki). case
m
A k I assume:
3 h r-am,
a k I.
It
h F" k I, k I A n 2
follows:
(see
I.
h A n2 h 6 C(112,n2) i r-m
such
~i F" ~mt i ~ m, Hence 1.2.
that
ak I
k I in c o n t r a d i c t i o n am
A mk I = k I and
We~assume
First
s E C ( 1 1 2 , n 2)
that
s = at.
It remains
r 6 C(111)
1.2.1.
If
s " l k I , ~r
1.2.2.
If s A k I, a s s u m e h 6 C(111)
(iii)
~ak
and
s = mr.
s 6 C ( 1 1 2 , k I)
3h such
(see
r 6 C(111,ki).
6[D I] = D 2 a n d
We
have
a)
a n d b)
Let
to
to
show are
m 6 C(111)
pos(111,m)
I. A s s u m e hence
m
points
s "lk I or
to
f)
c),
are
in t h e
d),
f)
s A k I.
r 6 C(111,ki).
infer to
proved
analogously.
definition
follow
s A k I.
from
(2214)(ii). (ii) ; it
e). and
m
A k I. W e
either
m
A n I . It f o l l o w s ,
m = 6m.
a)
such
k I. N o w
and we
¥ [ D 2] = C ( 1 2 1 , k 2)
= pos(121,m)
n I is m i n i m a l ,
implies
F ak I = k I i n c o n t r a d i c t i o n
immediate;
show
h P- r,
(i))
Thus
~ r 6 C(111,ni)
r ~ k I and
that
ah
3.
thus
r 6 C(111,ki).
I = k I, h e n c e
= C ( 1 1 1 , n I)
r A k I and
and
to s h o w :
~h E mr = s a n d
remains
Since
that
show:
such
note
A k I.
mm 6 C(112,ki).
s 6 D I and will
Clearly,
and
to m
3 r 6 C ( 1 1 1 , k I)
that
2.
h = al
Moreover,
have
to d e r i v e
6m = m a n d
. A n I or m that
m
pos(111,m)
"I n I h o l d s .
A n 2 and m = am = = pos(112,m)
Bm = 7m,
= pos(i22,m)
=
37
pos(121,m). 2. N o w
consider
is d i s j o i n t it can be
from
ml, .... mk,
~m ~ which From
hence
$-2m ~
(2211).
substitutions
Lemma:
of
according
in 1.1.
we
conclude event
=
6m ~ nl, of m
# ~m, we
sequence
to
which
(228).
we
infer
Hence by
~m = m.
(2213):
[]
expresses sub-bodies,
a sort
of c o m p o s a b i l i t y
can be e x t e n d e d
for
to the case
sub-bodies.
L e t kl,
ni
k, w h e r e
n i A k I for i = 1 , . . . , k . are
A k I. As
....
of d i s j o i n t number
m
pos(111,nl)
In the
infinite
= pos(112,n1)
lemma,
because
Any m i
6m. = m. and l l
(ii)
= pos(112,m).
preceding
(2225)
6n I : n I and
is i m p o s s i b l e
of a f i n i t e
latter
= {nl,ml,...,mt}.
By a s s u m p t i o n ,
~m ~ m by
pos(111,nl)
let M(m)
V i : 1,...,k,
a countable
~-Im ~
pos(111,m)
The
Using
obtain m G
that
= pos(112,mi).
pos(112,n1).
and
n I and k I, the
shown,
pos(111,mi)
would
the case m ~ nl
Further,
the n i are m i n i m a l the
following
and
substitutions
assumed:
©©
I©©I
@ @ fig.
(2226)
38 SIo
=
(110,n1,~,~1,111,n~) !
!
$11 = (!11,n2,~2,e2,112,n2)
$I ,i-I = (ll,i-1'ni'~!'~i'll li'n!i) !
S1,i
l
= (ll,i,ni+1,vi+1,~i+1,11,i+1,ni+1)
!
$I , L-I = (11,L_1,nL,v L',~L,II
L,nL )
SI,L
= (11,L,k1,K1,6,12,L,k 2)
S2,L
= (12,L,n~,vh,Yt,12,L_1,nL)
$2,i+I
= (12,i+1,nL+1,gi+1,Yi+1,12,i,ni+1)
S2,i
= (12i,n~,vi,Yi,12,i+l,n i)
$21
= (121,n~,v1,Y1,120,n I)
If V i=I,..
,L, pos(12,i_1,ni)
6
= YI' .... YL 6 ~L,...,~I def
i, w h i c h
4.2.
n. C l
imply by c o n s t r u c t i o n
4.4.
n i A nk,
k 3. T h i s w o u l d
under
n¶3' k3
violate
which are
since this w o u l d
s.c.
nI 6 NI. for ~2 ~
n3"
In this c a s e n i is i n v a r i a n t
83 . H e n c e n i A k 2 is in c o n t r a d i c t i o n
k2•
$IO
= pos(12,i_1,ni)
... SIL , S2L,...
( 1 1 , k 1 , ~ 3 , 6 , 1 3 , k 3) and t h e r e b y
w e can a s s u m e
need only apply (2228)
by
since n k is m i n i m a l .
however
the a b o v e
for all k > i,j.
5. We h a v e p o s ( l l , i _ 1 , n i ) sequence
impossible,
n I• { N 3. m NI,
all Yk' k > i a n d
to n i C
are s a t i s f i e d ,
is i m p o s s i b l e
n[ for s o m e j ~ i is also 3
ni C
is p o s s i b l e
13,i:
4.1.
4.3.
s.c.
This
to ni ~ 13, i. S i n c e the n i are minimal, t h e r e
4 possibilities
In sequel,
a substitution
substitutions
$3, i : 1 3 , i , n i , ~ i , Y i , 1 3 , i _ 1 , n i) for i=k...].
only
the
(i'2 , k , k 2 ,~3,~3 '13, k ,k3).
4. Set Sl, L = S~, k 0 S~, L a n d c o n s t r u c t
simply
implies
s.c.
Vn, (nCl~, k and nAk2) $3, k :
t h a t the s.c.
R(~)
spatial regions. written
to the
~1 ~ ~3"
is a l w a y s
satisfied
u s e d in the p r e v i o u s
since we
proof.
= PoS(~P
/////////
l I "
Y3
r-
12
11
fig.
(238)
13
50
(239)
Definition:
The
f r a m e ~ 6 F w i l l be c a l l e d
iff the f o l l o w i n g that k ~ m,
property
holds:
F o r all k, m,
In this c a s e w e w i l l w r i t e s u b s e t of i n e r t i a l
pos(12,k) (k,m, ll,n)
= pos(n,k). ÷ 12 .
jwl///////
,ni!
m
m
11
12 fig.
Axiom
J1:
T h u s we p o s t u l a t e the
further
arbitrary The
(2310)
J % ~. that
inertial
developement
inertial
following
a configura-
f r a m e s w i l l be d e n o t e d by J c F.
@iI (2311)
frame,
11, n £ B such
11 6 Bm N ~ and n £ B k D ~p,there e x i s t s
t i o n 12 6 Sm n ~ s a t i s f y i n g
The
an i n e r t i a l
frames
can be f o u n d and w i l l
of p r e - g e o m e t r y
within
some
perform
f i x e d but
f r a m e ~ 6 J.
lemma
is an i m m e d i a t e
consequence
of the d e f i n i t i o n
(239). (2312)
Lemma:
(i)
k ~ n E m and
(ii)
1 6 B m and
(iii)
(k2'm'h1'q)
(k,m,h,p)
(k,m,h,p) ÷ q1'
÷ q implies
q £ Bm a n d k I ~
p o s ( q , k I) = p o s ( q l , k l ) . (Use a x i o m B2.)
+ q implies
(k,n,h,p)
(k,m,l,p) m implies
÷ q
÷ q.
51
(iv)
(k,m,h,p)
÷ q and pos(p,k)
(k,m,h,p)
÷ q.
(v)
h [-k
and
(2313)
Definition:
(i)
A
(k,m,l,p)
(positional) =
(2210) (vi)).
(ii)
~ is c a l l e d
(iii)
Two chains
11
(~2,k2)
cyclic
danger
12 ...
iff
of p o s i t i o n s
where
11
(~2,k2)
12
T ~ (Pl,kl)
11
(P2,k2)
12 ...
=
...
two p o s i t i o n s
I
for
is e i t h e r f " o r
of c o n f u s i o n
--I
we may write:
(~N,kN).
congruent,
{ (~i,kI)
, such that
(nN,kN).
(nl,kl)
d, ~ are c a l l e d
In p a r t i c u l a r ,
÷ q.
(~ ,k ) 6 Pos
I v (~v+1,k +i), Without
implies
(h,m,l,p)
is a s e q u e n c e
(~1,kl;~2,k2;...~N,kN),
~ (nl,kl)
(iv)
~ q implies
N-chain
~=I...N-I I (~v,kv) (see
= pos(p,k)
~ [] ~, iff
(~N,kN)
and
(PN,kN). (~i,ki),
(~2,k2)
are c o n g r u e n t
iff
kI = k2. (v)
An N - c h a i n
~ =
transportable an N - c h a i n Clearly, (vi)
Any
A cyclic N - c h a i n
2-chain
(2214) Proof: (2315)
Proposition:
and each
is:
V
~ (~1,k])
T
6 Pos
there
and s a t i s f i e s
satisfying
transportable.
exists
o ~ T.
iff it is w e a k l y
(v) will
frames
(239)
This can easily
is w e a k l y
be cyclic. is j u s t : be g e n e r a l i z e d :
transportable.
[] Any
(~],k]), 11
V (p,k)
transportable
of inertial
By induction.
That
is c a l l e d w e a k l y
(using a x i o m B3).
Any N-chain
Proposition:
(~N,kN)
(p,k)
a is c a l l e d
property
is w e a k l y
...
contains
T is unique
the d e f i n i n g
11
iff V ~ 6 {I...N}
Y which
transportable Thus
(~I,ki)
two p o s i t i o n s (~5,k5)
(~2,k2)
...
can be joined by a 5-chain.
6 Pos (~5,k5).
there
exists
a 5-chain
52
Proof: Aldef=
By
(2234) (i) there exists
reg(~i'ki)
p
pi t
?..,> p/~
commutes
(~ d e n o t i n g
the c a n o n i c a l
If g : P ÷ P is a n o t h e r
map,
surjection).
we have
f o g = ~ 0 g and
map
60
= ip/~.
We will
so is ~ a n d ~
I = ~-I
write
~(~I,~2,k) mappings
(2330)
If f is b i j e c t i v e ,
= T(~1,~2,k) obtained
in this
Theorem:
Proof:
By
: R ÷ R
and
that A < B implies immediately
Finally
we
are
to
T is a s u b g r o u p
from
lift
set of t r a n s p o r t
of A u t ( R , < ) .
TA ~ ~B for all
follows
by T the
way.
T is a s u b g r o u p
(2329),
denote
of Bij(R).
If r e m a i n s
T 6 T and A,
B 6 R. B u t
(2324) (vi).
transport
to show, this
[]
mappings
to the
lattice
of r e g i o n s
(R,O}.
o n the a r r a n g e m e n t
REGIONS
3.3
by
intervals
altering
a I < a l + I b y al ~ al+ I, t h e r e prefilters,
]a,b[.
T b 6 x
with
of a,
at l e a s t o n e p o i n t " .
F the o r e f i l t e r
U D F and x = lim
generated
U. It f o l l o w s :
by
72
~ b A b % O T b < a a6x
x6a.
(333)
Proposition: uniformity
Proof:
(BI )
We in
[BGT]
Nd c b d
have
to
P
6 x.
Set
prove
a ^ T b such
N U ~ y
L NvY ,•
~-
NV
~
y,
where y £ P and ~ 6 T is arbitrarily In order to show property -I (y) of points ~U,V transitively
chosen.
(iii) we notice
y 6 P/N V are homeomorphic
on P/N V and ~U,V is equivariant.
= NvX~-C---~eJN V in order to calculate
:
that all inverse
~
~
because
T operates
Therefore
the inverse
images
we may take
image:
Ivc e JNv
= nU[~vI[eJNv ]] = ~u[JNv] = JNv/JN u.
Now consider notation
[]
an arbitrarily
by writing
chosen U £ U. We shall simplify
our
N U = N, Nx = x, T/N = T, P/N = P, JxN/N = J.
115
Let T be the Lie algebra of T and d the subalgebra subgroup
J.
Consider
any 3 6 J. The C~-mapping
onto e, its derivation
belongin~
to the
t ~ J t 5 -I , t 6 T, maps e 6
at the point e thus being a linear
endomor-
phism of TaT ~ T, which will be denoted by J
:
T-+
(419)
T
Lemma:
Let t 6 T and I 6 ~ , then
exp(It)
Proof:
~-I : exp(l~(t)).
The left hand side defines
thus is of the form exp(It'), the possible
definitions
transformation
j ~
is a restriction
9.6).
It is faithful,
(j~x=~jx=~x=j=e). definite
represented invariant
complement, Consider
inner product,
[]
of the group J, of T
no central~elements T may be equipped
(see [F&V] except with a
denoted by , such that J is
endomorphisms
to all 9, hence this holds
(see [F&V]
35.1).
d is
also for its -orthogonal
which will be denoted by K.
the following
K C-~T exp~ ~
(4110)
representation
Since J is compact,
by one of
5.6).
a linear representation
since J contains
of ~,
~, namely by the induced
(see [ABR] Def.
of the adjoint
by -orthogonal
w.r.
= t' follows
of the derivation
forms
which
positively
t' 6 T. ~(t)
of smooth curves
The assignement
a l-parameter-subgroup
~ ~T/J
C=-map
f:
~ P, that is:
Definition:
Its derivation
composed
at O, f'
f(X)
= def
(expX)
x for all X 6 K.
= Tof, decomposes def
in the following
way:
116
K~-~T
To,~
~ r& '~
~ r3.; (,~/~) ~ r::: ~'
Td
T = J • K
where
z denotes
Therefore,
the c a n o n i c a l
j
= K
quotient
up to i s o m o r p h i s m s ,
local C~-diffeomorphism
J~K
~
map
f' is e q u a l
a n d for a s u i t a b l e
O • K + O • K/J. to Id K. H e n c e
f is a
x-neighbourhood
U the
restriction f-11U
: U ÷ K ~ ~P
is a C ' - c h a r t canonical
of P a r o u n d
chart. (see
[K&N]
(4111)
Proposition operates
coincides f-1
(compare
[FRE ]
on P by l o c a l l y
= ~(k)
exp and ~ are l o c a l l y
2.7.): orthogonal
transformations
via
chart.
~IK is o r t h o g o n a l
w i t h 3~ w h e n
3 f(k)
since
to as the
I, I 4.2.).
the canonical
Since
x. It w i l l be r e f e r r e d
It is e v e n a n a l y t i c a l ,
analytic
Proof:
the p o i n t
computed
for all
it s u f f i c e s
to show that
in the c a n o n i c a l
chart.
3 locallY
T h i s means:
3 6 J and k 6 K.
It follows: f(k)
=~ 5 ( ~ o e x p ) ( k ) = 3 (exp k) : 3 (exp k) 5 -I
J.
f-1 ~ f(k) = l o g ( j ( e x p =
(4112)
3 (k),
Lemma:
k)) ~-1 by
There
(41 9 ) .
exists
[]
a local C ~ - i n j e c t i o n
T : U ÷ T such
117
that
~(y) (x) = y for all y in some n e i g h b o u r h o o d
of x.
oo
Being
Proof:
a submersion,
v o T = Id U
(see
[B&C]
Identifying
T/J = P, we may
v has a local
Prop.
6.1.4.). express
v T(y)
= ~ J where
a 6 T such that ox = y.
Hence
T(y)
6 J
(4113)
Theorem:
and T(y)(x)
such that T o p e r a t e s
Proof
(see
[F&V]
inner p r o d u c t
= aj(x)
P may be e q u i p p e d
6.4.3.1,
= y in the form
= a(x)
with
isometrically
[K&N]
T,that means:
Let y 6 U.
T(y)J
= aj,j
C -section
2, X 3.):
= y.
a Riemannian
metric
g,
on P.
The p o s i t i v e
on K ~ T ^ P has to be t r a n s f e r r e d
definite
to the o t h e r
X
tangent
spaces
T~ P, z 6 P. This m a y be done by the linear
I^ f : T^ P ÷ T ^ P, w h e r e x x z The c o n s t r u c t i o n satisfying
by
on the choice
of f. Let g 6 T also
f-] gx = x, j
Y~ g = T~ f 0 Ti j, w h e r e T ^ P invariant
f 6 T, fx = z.
does not d e p e n d
gx = z, then
isomorphism
= flg £ ~, def leaves the inner p r o d u c t
Ti j
in
(4110).
X
In this way an inner p r o d u c t transporting
maps
differentiable Consider with
Hence
-I
= T^z g
o T~ g
-I
-I
to d e p e n d
(4112),
l o c a l l y.
hence
The
on z^ in a
C ~ -
z ~ g~ is C ~ too.
fixed
and T~(hog) , the p r o d u c t
= T~ h is an isometry. isometrically
g is u n i q u e l y
the claim only
way by use of
T operates
Whereas
can be chosen
globally.
any z 6 P and h 6 T. Let g 6 T such that gx = z. T o g e t h e r
(T~g)
T~(h0g)
g~ on T~ P is d e f i n e d
on
determined
that T C o n s i s t s up to p o s i t i v e
(P,g).
[]
by the inner p r o d u c t
of isometrics, definite
on T P and
the inner p r o d u c t
linear maps
commuting
is
with
the
118
r e p r e s e n t a t i o n of J on K. At any case, remains
4.2.
a p o s i t i v e scaling factor
facultative.
M O B I L I T Y AND D I S T A N C E M E A S U R E D BY CHAINS
We now turn to the last and d e c i s i v e a x i o m of Freudenthal. developed
It is
from earlier p o s t u l a t e s c l a i m i n g for i n s t a n c e that t w o
sets of points, w h o s e internal d i s t a n c e s are p a i r w i s e equal, may be m a p p e d onto each other by a
(global)
using the notion of a metric, Freudenthal
(421)
isometry
"mobility"
(and s i m i l a r l y by Tits)
(Birkhoff). W i t h o u t
is now f o r m u l a t e d by
in the following way:
There exist two points x, y E P such that the orbit Jx y dissects
the space P,
w h e r e "dissection" means:
(422)
Definition:
Let B be a t o p o l o g i c a l
space, A c B. A is
said to d i s s e c t B, iff B~A is not connected.
The p o s t u l a t e
(421)
m e a s u r i n g distances. (3514))
is i n t i m a t e l y c o n n e c t e d w i t h the p o s s i b i l i t y of The c o n v e r g e n c e of the chain q u o t i e n t
(see
cannot be p r o v e d on the basis of the axioms RI to R5, as is
Shown by the f o l l o w i n g
(423)
C o u n t e r example:
R is the lattice of b o u n d e d open subsets
of 2 2 , T is induced by translations.
Since the chain links do not freely rotate, l(x,y,a) h l(u,v,a)/a £ R
the limit of
o
depends on the shape of the links as is shown in the following
119
figure:
] I j i
]
I I
I....
I
fig.
Clearly,
t
(.424)
the counter example does not satisfy the r e q u i r e m e n t
(421).
This is of course not accidental as c o n v e r g e n c e of the chain q u o t i e n t and m o b i l i t y are e s s e n t i a l l y equivalent,
(425)
Theorem:
as we will show.
In a system in which axioms RI to R5 hold,
the
following 3 assertions are equivaleDt: (i)
There exist two points x, y 6 P such that the orbit Jx y dissects the space P
(ii)
(Freudenthal).
There exists a point x 6 P and a n e i g h b o u r h o o d V of x such that each orbit Jx y' x # y 6 V, dissects the space P
(Tits). Further,
(iii) The chain q u o t i e n t w.r. on regions
T is a Lie group. to
(R, 0
a I < a ° and
a 2 < a ° V y 6 b:
c
conclude
of the
is f u l f i l l e d ,
~,
the
space
following
the
chain
quotient
A(x,y,u,v).
assumptions the
of
space
in
follows:
V f 6 R
completeness
and we m a y
will
image
b ~l f = ~
< I)
the
thus
that
l(x,y,a I )
Q(x,-,-)
filter
H a ° 6 R ° V a I, a 2 6 R ° s u c h
(429)
each
is C a u c h y - c o n v e r g e n t .
of the m a p p i n g
formulation
x 6 f
(428)
x 6 P and
to c o n v e r g e
on r e g i o n s ) .
The
By
is said
f 6 S ° containing
directed
Fc(P~f,~)
quotient
some
(y~ l(x,y,a)/l(u,v,a))
and
The
iff
: [R o] ÷ F c ( P ~ f , ~ )
[R o] = R o / T
gence
(R, I.
We shall i d e n t i f y K and ~ P
(see
(4110))
such that the inner p r o d u c t
on K c o i n c i d e s w i t h the usual inner product on ~ P . W e recall that w.r. linear,
to the c a n o n i c a l chart f-1
orthogonal,
: U + ~ P , f,1 ~ f consists of
locally d e f i n e d m a p p i n g s
and dim Jy ~ p - I a c c o r d i n g to
~P
÷ ~P.
(4213). We define r =
Let be y E U lif-lyll and
S(O,r)
= {~6~PILI~II=r} . We may choose y 6 P such that f-1[U] def c o n t a i n s S(O,r) and hence the image of the orbit y
= f-1 ~ c S(O,r). Y is a c o m p a c t s u b m a n i f o l d of S(O,r) of def d i m e n s i o n p - I, hence open in S(O,r). By v i r t u e of p > I, S(O,r) c o n n e c t e d and we infer Y = S(O,r). £ ~P
~
linearly.
l~,
proves:
The c o n t r a c t i o n s
O < I < I map J - o r b i t s onto J-orbit,
Hence in some n e i g h b o u r h o o d
a sphere w.r.
is
since J operates
f-1[V] c f-1[U]
each orbit is
to the c a n o n i c a l chart and thus d i s s e c t s P. This
125
(_4216)
Proposition"
In a certain n e i g h b o u r h o o d V of x each
o r b i t Jy, ~ # 9 6 V, dissects _D, if dim P > I.
Now we are ready if T can be shown to be a Lie group, = T and
(425)(ii)
follow
either by
(4215)
since then
for p = I or by
(4216)
for p > I.
(4217)
Lemma:
For all U, V 6 U the following holds:
dim P/N V = O or dim P/N v = dim P/N U.
Proof:
Let us assume U c V and p = dim P / N u > dim P/N V = q > O.
The s u b m e r s i o n VU, V : P / N u ÷ P/N V is e q u i v a r i a n t w.r. o p e r a t i o n of J J-orbits.
By
(see
(417)
(418) (ii))
to the
and hence it maps J - o r b i t s onto
the same holds for its d e r i v a t i o n
TNuX ~U,V : TNux(P~Nu)
÷ TNvx(P/Nv)'
which can be identified w i t h a
n o n - t r i v i a l linear p r o j e c t i o n ~ : ~ P
÷ ~q.
J - o r b i t s are the spheres in ~ P
~q.
resp.
As m e n t i o n e d before,
But a sphere S p-1
the
is not
p r o j e c t a b l e onto a sphere S q-l, 0 < q < p, because for instance -I (O) D S p-1 tion.
# ~ implies O 6 ~[S p-I] = sq-1 , w h i c h is a c o n t r a d i c []
(4218)
Theorem:
T is a Lie group.
Proof:
Let us assume the c o n t r a r y and consider a c o u n t a b l e infinite
d i r e c t e d s u b - f a m i l y of U according to ding i n v a r i a n t subgroups Ni,
(411)
i 6 ~ . By
and call the correspon-
(4217)
the sub-family may
be chosen in such a way that the spaces P/N i have the same dimension. Hence the submersions images
vi+1,i
(see [B&C] Prop.
: P/Ni+I
6.2.1.).
÷ P/Ni have discrete inverse
126
By
(418) (ii),
open
(see
compact spaces
[BGT]
space and
subgroups only
for
all k ~ k By
J N i / J N i + I is d i s c r e t e .
(413)
III§
2.5 Prop.
is the
topological
consequently of the
contains
f o r m JNj.
finitely
14)
many
Further, subgroup
only
i E ~ . Thus
such we
two that
that
we may
we have
P/N
different z ~ W.
~ T/JN,
hence
points
y,
subfamily
we obtain
PROOF
(4215)
that
OF
P/N k = P / N k + I ,
we may
~ : P x P+
We
consider
confine
~
of
JN k = J N k + I for
let a £ R ° w i t h
means
N k % {Id},
a neighbourhood
(see
U in such
(313))
a way,
there W of y
containing
that
because
that
N k c T(V)
z.
If
for
N k z is c o n t a i n e d 0
(iii)" ourselves
connected The
to the
case
Riemannian
dim P >
manifold
corresponding
metric
I. We
recall
on w h i c h
shall
be d e n o t e d
.
two p o i n t s
be a s s u m e d
consider
~
isometrically.
by
later
of d i f f e r e n t
which
Because
of W
a contradiction,
"(ii)
P is a c o m p l e t e ,
operates
of
J N i + I ~ JN i is v a l i d
in W and y E N k z is i m p o s s i b l e .
By
number
assume
z 6 N k y and
L e t V be a k e r n e l
the
k Z ko,
4.2.2.
number
.
O
construct
some
a finite
a finite
We conclude
and
of JN i. But JN i as a
s u m of o n l y
for all k Z K ° and y £ P, N k y = N k + I y. exist
J N i + I is a c o m p a c t
to be
x, y 6 P and
a region
sufficiently
small
a < ao,
(R,c,T)-chains
be a r b i t r a r i l y instead
of
a O £ R O which
(depending
chosen.
By
(R, 0 so small,
is an i s o m e t r i c m a p
because
there 3.6)
a l w ays
f[S(O,r)] map,
t h a t each
("minimizing"
exists
in
"convex"
a n d P is a h o m o g e n e o u s
space.
r I < r 2 ~ 6 (r I) < 6 (r 2) .
r I < r2,
such that ~(0)
f[S(O,rl)]
at a p o i n t
z 2 6 f[S(O,r2)]
and ~ : [O,~(r2)]
= x, ~(~(r2) ) = z 2. It m e e t s
÷ P being
the o r b i t
z I # z 2. H e n c e
< $(X,Z 2) = 8(r2).
The c o n v e r s e
holds
Thus
the f o l l o w i n g
locally
S(O,r),
to x. r ~ ~(r)
I, IV Th.
a geodesic
= ~(X,Zl)
I, IV Th.
of x, in w h i c h
h e n c e all p o i n t s
1 S ~(r o)
is p o s s i b l e
(4222)
~(rl)
are s p h e r e s
This w i l l
a
f-1.
f is c o n t i n u o u s .
neighbourhoods
[K&N]
y : [O,d] ÷ P such that ¥(0)
of ~ - i s o m e t r i e s ,
This
we h a v e to c o n s t r u c t
minimal.
j o i n i n g x and y. By
h a v e the same d i s t a n c e because
is "almost"
L e t V be the n e i g h b o u r h o o d
the c a n o n i c a l J
for X(x,y,a)
for any s t r i c t l y m o n o t o n e
notions
real
[]
function.
are s y n o n y m o u s :
O r b i t Jx y' I m a g e w.r. Equidistant
to f of the s p h e r e sphere
S(O,r)
{ z 6 P I 6 ( x , z ) = 6 ( r ) }.
N o w a s s u m e a ° 6 R ° is s u f f i c i e n t l y Further These
let Xo, Yo 6 a be p o i n t s
exist because
c ~P ,
a is compact.
small that
A(a)
I
S A(a o) < ~ ~(ro).
of m a x i m a l
distance
6 ( X o , Y O) = A(a).
Consider
a congruent
mapping
128
6 T such implies
that
Tx O = x.
If Yl
= ~Yo' 6(x'Yl) def 0 < r < r o.
J x Yl = f [ S ( O , r ) ] ,
Define
K(O,r)
Either
the
f[S(O,r)]
=
= ~(Xo'Yo)
< ~(r°)
{ ~ E ~ P l II~II< r}.
geodesic
y[O,d]
at a p o i n t
fs c o n t a i n e d
x I, s i n c e
in f [ K ( O , r o ) ]
f[S(O,r)]
= Jx Yl
or
dissects
it m e e t s P.
Yl
....
....../ y
x2 xI
Yo o
fig.
In the
first
In the
second
case we put m = O and proceed
c a s e we h a v e
there
exists
chain
to be c o n s t r u c t e d .
Otherwise
we
some
j 6 Jx
repeat
the
yl[A(a),d]
for y etc.
Evidently,
after
a such
that
(4223)
m steps
6 (Xm,Y)
x I = y(t),
such
that
x I = j YI"
construction
< A(a)
and
indicated
0 < t S d.
If y = x I, w e
we obtain
as
are
Because
We put
x I 6 Jx Yl
T I = jT for the
finished.
substituting
a chain
below.
between
x I for x,
x and x m of o r d e r
129
(4224)
The
m = [ A(a)
latter
geodesic ~(x,y)
~ "
follows,
and
because
are p o i n t s
~ ( x , x I) = ~ ( X l , X 2) = ... g ( X m _ 1 , x m)
on an
= g(a),
(isometric) hence
= ~ ( x , x I) + g ( X l , X 2) + ... 6 ( X m _ 1 , x m) + ~(Xm,y).
N o w we h a v e to c o n s t r u c t chain,
X,Xl,...Xm,Y
the last two c o n g r u e n t
mappings
of the
Tm+ I, Tm+ 2. L e t be ~, ~ 6
Xm+ I
xm
Y
fig. s u c h that ~ x ° = x m,
(4225)
~ x O = y and put x' = ~ Yo' y' = ~ Yo" We n e e d
the f o l l o w i n g
(4226)
Lemma:
Proof: defined
J
x
x' D J m
The geodesic
y
y'
# ~.
yI[d(X,Xm),d]
can be e x t e n d e d
for all t 6 ~ , s i n c e P is c o m p l e t e
Consider obtaining
extensions a geodesic
([K&N]
to a g e o d e s i c I, IV Th.
at b o t h ends Xm, y by a l e n g t h of A(a),
4.1.). thus
130
y'
: [~(X,Xm)-A(a),d+A(a)]
2A(a)
+ 6(Xm,Y)
< 3A(a)
Hence
the p o i n t s
÷ ~
with
< ~(ro).
= y' (~ (X,Xm)-A (a)) def
and
= y' (~(X,Xm)+A(a)) def
satisfy
~(Xm,X)
= ~(Xm,~)
= A(a)
length
By the choice
and t h e r e f o r e
of ro,
y' is i s o m e t r i ~
lie on the orbit
Jx
x'. m
Further: 6(x,y)
= ~(x,x m) + 6(Xm,Y)
> A(a)
(~,y)
= 6 (~,x m) - ~ (Xm,Y)
< A(a)
Hence
x lies
A(a),
which is
and Jx
x' m assertion.
(4226)
in the i n t e r i o r
is
J
Y connected
y',
o
of the sphere
x lies
in the
and contains
x,
around
exterior,
y with J
Y ~. T h i s p r o v e s
y'
radius dissects
the
D
proves
Xm+ 1 6 J x
just
and
the e x i s t e n c e
of a
point
x' n Jy y'. we put Xm+ I = ~ x' = ~ y',
and Tm+ I = j ~,
Tm+ 2 = ~ ~. This
yields
the chain
~ 6 Jxm'
~ E Jy,
[x,y,a,T I .... T~]
where m
=
if x
= y,
m
m + 2 if x m # y. A minimal hence
chain
k(x,y,a)
(4227)
between S m, and,
l(x,y,a)
x and y m u s t by
_< [ A(a)
Let d £ R ° be such that ll(x,y,a)-l(x,y,a')
] + 2.
a' = Nd(a)
I -< I (see
~(x y,a)
< [~(x-t-~!)] + 3 _< ~!x,y) [
A(a)
J
satisfies
(3711)).
> l(x,y,a'),
-
(not strictly),
(4224):
k(x,y,a)
'
be s h o r t e r
hence
A(a)
+ 3 "
a c Nd(a)
implies
P
131 Together
(4228)
with
(4221)
follows:
6(x,y) A(a)
< l(x y,a) '
< 6(x,y) - A(a)
6(U,V)
62
62
61 11 - 3 ~ ~--
From
pair
x % y and u % v in sequel.
61
61 / 1 ' ~ A : ~22 { ~ /
+ 3,
A -
A
62
1 1+__3_3___ X2-3
follows
B,
def
62
I A ~ 11_3
, hence:
361 61 + XI-3 B
61 /I +
3
r2
137
SSnce a has a diameter
less than ¢/3, there exists a point w on the
a-chain between x and y such that r 2 + ~2 ~ < fi(.x,w)
minimal
~ r 2 + E.
Now
fi(~,~)
s ~(.~,w,a)
(&,~,a)
~ ^
^
+ E/3
+ ~/3
^
~(u,v,a) 2 2 Sr2÷~c, which is a contradiction. NOW consider the canonical
f-l:u÷
D chart around x £ P (see section 4.1)
K
and the dilatations Dt : K ÷ K Z ~ t-Iz,
t C ]0,1].
Each congruent mapping
~ £ T induces a local congruent m a p p i n g
Dt d -1 • f Dt 1, w h i c h o p e r a t e s Intuitively canonical
speaking,
in the O-neighbourhood
f-l[u]
one looks at the congruent mappings
chart with a m a g n i f y i n g
glass. One then expects
o f K.
in the the space
to look almost Euclidean. Indeed,
by
(4111)
f-1 ~ f consists of local,
commuting with dilations.
It remains
orthogonal
to examine transformations
occuring
in exp K. We set for t E ]O,1] and X £ K
(4238)
~(t,X)
= Dt f-1 exp(tX) f Dt I def and notice that the local transformations generally be non-linear.
However,
a p p r o x i m a t e d by translations (4239) Lemma:
are defined,
~(t,X) will
fort t.T_Q1__thgy may be
of K, as we will show.
Let X,Y,K 6 K and e,B £ ~
expression
transformations
be such that the following
and put ~(t,X,Y)
= T(t,X)Y. def
138 ^
(i)
K = T(t,X,Y)
(ii)
T(t,X,O)
(iii)
T(t,~X,BX) ~(t,X)
(iv)
~ exp(tK)x
= exp(tX)
exp(tY)x,
= X,
-I
=
(~+B)X,
= ~(t,-X).
Proof:
(i)
By
(4110),
f(X)
K = ~(t,X,Y) hence (ii),(iii) locally
(iv)
are
chosen
(4239) (i) y i e l d s
and,
f(tY)
exp(K1)x
a method
f-1[U]
of
T(t,X),
= exp(tX)
exp(tY)x,
following
fact:
exp(tY)x.
consequences
from
by d e f i n i t i o n
= exp(tX)
= exp(tX)
diffeomorphic,
K I and K 2 are
(expX)x
~ f(tK)
exp(tK)x
and
=
of the
= exp(K2)x c
implies
Since
f is
K I = K 2, p r o v i d e d
K.
[]
of c o m p u t i n g
K = T(t,X,Y).
Find
a Z 6 T
satisfying
(42310)
exp
Z = exp(tX)exp(tY). !
This
can be a c c o m p l i s h e d
(see
[VAR]
written
(42311)
2.15.).
Z(X,Y)
as an a b s o l u t e l y
Z =
[ haO
where for c
o
by
the
Baker-Campbell-Hausdorff
is a n a l y t i c convergent
w.r.
to
(X,Y)
t n Cn(X:Y) ,
the c n are p o l y n o m i a l
mappings
Y × I + I of d e g r e e
instance: = O
c 2 = l[x,y]
Further
= 7!~[x, Ix,Y] ] - 7~[Y, Ix,Y] ]
we o b t a i n
a n d c a n be
series
cI = X + Y
c3
formula
a locally
unique
decomposition
n,
139
(42312)
exp Z = exp K' exp J', K' Z ~ K', chart
(42313)
K'
=
Z ~ J' are l o c a l l y
and exp:
tK,
J'
a n a l y tic,
T ÷T are analytic.
since
the a s s i g n e m e n t s the c a n o n i c a l
If we set
tJ
=
we h a v e K = ~ (t,X,Y)
(42314)
6 K, J' 6 J w h e r e
and
K =
[ t n Kn(X,Y), J = [ t n J n ( X , Y ) , from w h i c h K n can be n~O n~O c o m p u t e d for any p o w e r of t in the f o l l o w i n g m a n n e r . Inserting exp(tX)
into
(42310)
exp(tY)
and u s i n g
= exp(tK)
exp(tJ)
(42311)
we o b t a i n
and
tn Cn(X:y ) = [ tn Cn(K:J ) n~O
n~O
tn Cn(
= n~O
~ tVKv(X,Y) : ~ t ~ J ~ (X,Y)) vaO u~O
The p o w e r
series
coincide.
Since c
are i d e n t i c a l o
iff the t m - c o e f f i c i e n t s
= O, no t ° - t e r m s
occur.
For the t l - t e r m s
we o b t a i n
t 1 Cl(X:Y)
= t 1 Cl(K:J)
Thus o n l y the t ° - p o r t i o n
modulo tm-terms, of c1(K:J)
m > 1.
counts,
which
is K o + Jo"
Hence: t(X+Y) and,
(42315)
= t(Ko+Jo) ,
s i n c e X + Y 6 K,
K O = X + Y, Jo = O.
T h e n e x t terms I KI = ~ [ X ' Y ] K '
are I X Y] J1 = 2[ ' J _
K 2 = I[X-Y,[X,y]]K
I
~ [ X + Y , [ X , Y ] O]
J2 = I ~ [ X - Y ' [ X ' Y ] ] J ' where
the s u b s c r i p t
corresponding
subspace.
c o u l d be e x t e n d e d homogeneous
K
(resp.
Further,
to o b t a i n
spaces.
j) d e n o t e s
the p r o j e c t i o n
[K,d] c K
a B.C.H.
formula
is used. for
onto the
The c a l c u l a t i o n s
(reductive)
140 Now we consider K-K ____90 = t
the norm of
[ tn-1 K = L(t,X,Y), n n>1 def
Since L is analytic
in
(t,X,Y),
t 6 ]O,1]. it has a b o u n d e d derivative
at
(0,0,0),
hence IIK(t,X,Y)-Ko(X,Y) II = tlIL(t,X,Y) II S t(llL(O) ii+itlliXiiliY1iliL I It), where ilL(O) II = llK1il = II½[X,Y]KII ~ CliXliliYli and t,X,Y are sufficiently We recall K(t,X,Y) (42316)
Lemma:
small.
= T(t,X,Y)
Theregxists
and Ko(X,Y)
= X + Y and obtain:
a connected O - n e i g h b o u r h o o d
W c f-1[U] c K such that ¥ ~ > 0 B to > O V t 6 ]O,to[
¥ X, Y £ ~,
II~(t,X,Y)-(X+Y) II < ~IIXII I[YII. Let us summarize: local mappings (t)
on K by means of the class of
T (t)
= Dt f-1 def
T (t) = ~(t,X)
The group T operates
= Dt f-1 ~ f Dtl " Each local t r a n s f o r m a t i o n def T f D -I t £ T(t) can be w r i t t e n as a product
j such that X = T(t)o and j £ f-1 ~ f
£ T (t) has a domain of d e f i n i t i o n
containing
= J'. Each def -I D(~) = ~ [W] n W. def
If we Consider the class of regions R' a6R,acU
and O£a'}
= {a'la'=f-1[a], where def in K, it is appropriate to speak of (R',c,T(t)) -
chains between points the chain quotient? O and Y £ W, say minimal
in W. What can be said about the convergence
Notice
that a minimal
[ O , Y , a ' , ~ t) .... T~t)],
chain between
is just the image of a
(R,c,T) -chain
[x=foD -1 (O) ,foDtl (Y) .foDt1[a'],~ . . . I. . provided
(R' ,c,T(t))-
of
that a' ~ D(~i(t)))
But this can be achieved by necessarily
independent
~11
for i=I . . . 1. (4237),
if a' is sufficiently
of t). Let us make the following
small
(not
141
(42317)
Definition:
S&(X,~)
{YEKI iJX-YiJ~e} , a n a l o g o u s l y :
= def
S< and S=. T h e n w e can state (42318)
the
Proposition:
B r > O such that Ss(O,r)
V V,Y 6 S=(O,r) lim O6R' Proof:
V t 6 ]0,1[
l(t) (O'Y'a) l(t) (O,V,a)
Let
c,r 2 in
exists
(4237)
r > 0 satisfying
f[Ss(O,r)]
This
by
is p o s s i b l e
c W and
and will
be d e n o t e d
be such that Ks(x,r2+E)
by d(t) (O,Y).
c W and choose
c Ks(x,r2).
(4236) (iii).
= d(x,f0DtIY) < r 2. def Thus each p o i n t w on a m i n i m a l
Now apply
(4237)
for
rI
= f 0 D~ I Y lies this m i n i m a l This
proves
(42319)
a-chain,
in K s ( x , r 2 + E ) ,
hence
c h a i n onto a m i n i m a l
provided
a c b, b e t w e e n
in W. T h e r e f o r e
(R',c,T(t))-chain
the assertion.
x and
D t o f-1 maps
between
O and Y.
D
Proposition:
Let V,Y 6 K satisfy
V c £ ]O,1[H
t o 6 ]O,1[V t 6 ]O,to[
liVii =
iIYiJ = r.
the f o l l o w i n g
2 assertions
hold: (i)
V a £ R' V T 6 T (t)
(ii)
If an def = S ~ n n(1+~)
Combining
the inequalities
l(t) (O,Y,an) n+_____!__1~ (1+e)n l(t) (O,V,an) Now the assertion
dissects
if n ÷ ~.
to show that for some V 6 S=(O,r)
the O - n e i g h b o u r h o o d
portrayed (42320)
S n(1+~) n+1
follows
We are now p r e p a r e d
we obtain
in the introduction
Theorem:
the orbit J'V
W. The idea of the proof has been (see fig.
(131)).
There exists a V 6 K such that W~J'V is not connected.
JLVII = r and
(We recall
that W was
assumed to be connected.) Proof: I. Let V 6 K and
llVLi = r. J'V is a closed subset of S=(O,r),
latter dissecting assume
W. In order to derive a c o n t r a d i c t i o n
the
let us
143
(I) J ' V ~ S = ( O , r ) . Let V X,Y
denote
the
6 S=(O,r),
<X,Y>
(2)
H Y 6 S=(O,r)~J'V
2.
Let We
inner
= r
2
chains
K. S i n c e
V X 6 J'V,
> O be
n
on
~ X = Y, w e m a y
H 6 6 ]0,1[
n 6 ~ , t 6 ]O,1[,s consider
product
J'V
and
conclude:
<X,Y>
f o r the m o m e n t
[O,V, a n , T o . . . T n _ 1 ] ,
is c l o s e d
where
~ 6r 2. arbitrarily
chosen.
a n = b n U c n,
(3) b n c S < ( O , e n ) I V,e n) , (4) c n c S< (~ and
~i = T ( t , ~ V )
The
chain
minimal
for
property
chain
i=O...n-1.
is e a s i l y
could
only
be s h o r t e r ,
(5)
I (t) (O,V,a n)
S n.
3.
NOW
consider
6 > 0 according
(6)
e
O s a t i s f y i n g
r 8r ~ ~n < ~
Let
t
to
analogously
(> 0 s i n c e
3n > I + s),
hence:
"
is c h o s e n
so t h a t
I
< n
some
3r 2(I+E)
Further, (9)
(42319).
proved
4n2 (i+c) r
(IIO)
£n
O s i n c e
(1+2a) (I+E)
Consider
an = b n U cn according
(42319) (ii),
-
]
e n < 2-n
to
I E < ~).
(3) a n d
(4).
By
A
144
l(t) (O,Y,a n) lim n÷~
= d(t) (O,Y)
l(t) (O,Y,an)
(12)
B n
E ~ V n ~ no o
< l(t) (O,V,an) (I+2e)
and by
(5):
I (t) (O,Y,a n) < n(1+2e). From
(2) it f o l l o w s
that,
I V) , (13) ¥ X E J' (--
4.
< I + e, h e n c e
It(o,V,an)
Now consider We w i l l
This
a minimal
always
(14) n 2 ~ 2+e 16r
< ~r2/n.-
assume
chain
[O,Y,an,T1...~l].
n Z no,
further
"
implies:
8__~r > 1 2+~ - 2n 2
> En (9)
I 4r ~ ~n + 2 e e n 4r(I-~
(15)
en/8r)
4r > I-E where
~n/~
prove
¥ i=I...I (16) < Y , W >
is s t r i c t l y
the f o l l o w i n g
iIWll -< 3r.
4.2.
"i=I" = def
positive
auxiliary
by v i r t u e
assertion
of
(8).
by i n d u c t i o n
V W E ~i[an],
< ir[r(~+e)/n+4Cn(1+~)]
(17)
If U I
'
the d e n o m i n a t o r
4. I. We w i l l
(18)
Z en, hence:
and
T 1 (O) we h a v e
~I = T(t'UI)
0 J1'
Jl £ J'
We m a y w e l l
confine
W E ~l[Cn]"
Let W = T I W o, W O E c n, and W I
ourselves
to the case O E T 1[b n] and = Jl Wo" def
Hence
on i:
145
W = T (t,U 1)w I and r llW III = IIWoll < ~ + E n-
(19)
From
(13) we conclude
(20) + < r[r(6+e)/n+4
which 4.2.3.
(24)
is
(16)
Combining
IITI(O) II =
I IIYI} IIW-j I (~ V) II -< 6r2/n + 4r ~n en(1+e) ]
for i = I.
(22)
and
(15) we infer
IIUIII < 4r
and may a p p l y
HWoll
Ui+1 •
holds: r < n + ~n'
= +
< ~r2/n + r en' (13) (26) < Y , W I >
6 J',
W o, W o 6 c n,
WI = 3i+I W o , W2 = W The
Ji+1
% ~'
< r(r6/n+En).
hence
IIYII IIWo-l_n Vtl
147 ^
4.3.1.
Let W i = ~i+I Vi' Vi 6 bn, and ~ = a
--I
and ~i+I
= d o i, w h e r e
d = T ( t , W i)
^
0 Ti+ I. F r o m
~ V i = 0 we infer 0 6 ~[b n] and thus ^
we may apply particular,
the results
of 4.2.
concerning
II~(0) II < 4r by v i r t u e
of
Iio(0) II = llWill < 3r by the i n d u c t i o n
~I to T. In
(24),
and
hypothesis
(17). Thus we
^
may a p p l y
(42319)(i)
A(ri+1[bn])
= A(oo~[bn]) 2
-< (I+¢) llUi+111 (27)
for both
2,
"spherical
line".
S 6 + v(G2) , "spherical
imaginary
line".
geometry".
5.
CHARACTERIZATION
The be
classification singled
OF EUCLIDEAN
of section
out by two
Vanishing
curvature
(ii)
dimension
3.
It w o u l d (R,
rotation some
e =
of V and D
group
mapping
D
v 6 V,
is c a l l e d
: E + E, d e f i n e d
is c a l l e d
generated
a
: V ÷ V satisfying
for all x 6 V and det D > 0 is c a l l e d
f i x e d A 6 E,
A. T h e
form A ~ v 0 A,
a proper
by t r a n s l a t i o n s
by D(v0A) rotation
=
(Dv)
a proper 0 A, f o r
of E w i t h
and p r o p e r
center
rotations
of
156
E will The
be d e n o t e d
linear
mapping
reflection; fixed
S
A 6 E,
: E ÷ E,
the
L 1 : V ÷ V, L l v
T(~)
of E, R(~)
Now
let
[TF
(S;~,G)
S : V + V,
will
as the
Iv;
that
(S,T)
LI,
is c a l l e d =
(Sv)
of E w i t h
I > O,
be d e f i n e d subclass
as the
of open,
be the
0 A
center
= def
class
Recall
(at l e a s t
that
structure A glance (533)
the
N t°p
slightly
set of p o i n t s
P
(327)
with
the
at F r e u d e n t h a l ' s
list
shows
Theorem:
Assume
the
Then
exists
a structure
there
such
Consequently,
situation
that
axioms
(P,Nt°P,T)
(R,c,T)
is e n d o w e d
RI
N
with
a of the k i n d
represented
(p,Nt°P,T)
(~,=,¥)
(E(~) ,T (~) ,T(~) )
fig.
[3
is [ T F - i s o m o r p h i c
(R,