VORLESUNGEN Fusdem
FACHBEREICH MATHEMATIK der UNIVERSITAT ESSEN ..
ii
'
Helt7
il-
V. B. Dlab
TO DIAGRAMMATICAL AN...
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VORLESUNGEN Fusdem
FACHBEREICH MATHEMATIK der UNIVERSITAT ESSEN ..
ii
'
Helt7
il-
V. B. Dlab
TO DIAGRAMMATICAL AN,INTRODUCTION METHODS IN REPRESENTATION THqORY' ,]
'
,Ausalbeitung: Riüard Dipper . ,,
l
I
e i f",
,l
1981 ,'
u/
+'' i/ 4 uu.iqi't i( -
/'t.< t '"
.1,: :i t'
r
1,,
VORLEST'NGEN aus dem FACHBEREICH UATHEMATIK
der UNIVERSITATESSEN
Iteft
7
V. B. Dlab
AN
INTRODUCTTON TO IN
DIAGRAMI.,IATICAL MEIHoDS
REPRESENTATION TIIEORY
Ausarbeltung:
Rlchard
19 8 1
Dlpper
Acknowledgements
These notes lectures
contaln
addressed
the materlar
to
the
graduate
presented students
rn a serres in
Algebra
of
at
the Essen durlng the surmer semester 1g7g. T should lLke to thank prof. c.o. Mlchler for hls klnd lnvltatlon to vlslt Essen, and the audlence for their partlclpatlon actlve ln the lectures. unlverslty
to
of
The alrn of
thl-s
some baslc
results
and conseguently tensor
algebras
brief of
the
course the
content
was to
expose
the
representatlon
theory
was restrlcted
to
and a few slmple
audience graphs,
of
a study
1llustratlons
of
of
the
theory.
As a result,
the reader finds a major overlap wlth the Me_ the Amer. ltath- society No. 't 73 and an omission of general theory of M. Auslander and I. Reiten.
molrs the
of
My special written tails
notes
are
due to
wLth great
r should
Department
thelr tatlon
excellent of
the
of
lr-ke to
Mathematics
typlng,
p.ichard
Dr. care,
and in many ways improvlng
Pinally, the
thanks
up the
of
contributed
supplylng
the
thank
Digper
original
alr
those the
de_
expositlon. secretalies
Essen University to
who has
missing
formal
who,
of by
presen_
notes.
Vlastimil
B. Dlab
CONTENTS Chapter
f
Valued
graphs
s1
Valued
52
The roots
Sg
Graphs wlth
Chapter
II
PAGE
graphs, of
1
Dynkln
and Euclldlan
graphs
graphs
valued
7
orlentatlon
Reallzatlons
of
1
11
valued
graphs
and its
20
repre9entatlons
s s s
1
X-reallzatlons
2
The Coxeter
3
Prejectlve
Chapter
ffl
Graphs
of
and representations functors
30
modules and extenslons
finlte
and of
The representatlons
of
s2
The non-homogeneous
representations
Dynkin
Euclld1an
Appendlx
graphs
56 of
60
of
85
graphs
'Blmodules Graphs
3f
graphs
The hornogeneous representatlons
s4 Ss
47
tame type
St
Eucll-dlan
20
of
Euclidian
and bimodules
type of
wild
100 type
ru)
A
Applicatlons
118
1
Algebras
118
2
Normal
3
Further
Appendix
B
Exanples
173
Appendlx
C
TabIes
180
form
problems
applicatlons
139 171
-1-
Chapter S 1
graphs,
Valued
graph
A valued rrith
Valued qraphs
r Dynkin
(I,d)
is
and
a finite
a set d ={(dii,dii)lar.
graphs
Euclidian
€N
u
(of
f
set
vertices)
together
€ I}(of
{c},i,j
vaiues)
L J
J L
satisfying i) li)
dlt=oforalli€I For every utj
= di1 fi
tj
Notice that join
€ f there
i
d, : i rJ
exists
for all
o L f a n d o n l y- i f
, If
d,. rl
j 1 Another valued graph ( l',d') (t,d),if Veltices,
( l,d)
is
a sequence 1 = ior that
the fi,
scalar
d:. )L
I o. fn this
i1,
multlples,
if n} c
For the rational
with
ft
g t
is
a subgraph of
(xi)l*iee,
s!'nnetric
bilinear
form
(1) :=
-f .i 'x. . y .
i,j
€ t
, there
ik = i of neighbours in
is
ccnnected.
-
i€r}withn= Bf
- I .
quadratic (r,r)
"l.
all
f
determj.ned up to
Of course we can nrite
=
definethe
lrl
by r (r,j)€f"f
d..f .x..;. rifixiYi
for
y I , I \ , .€ Q '
form tr*r'
,ä.
-
dijrj*i*j .1. ij
,
rvhere in edges
the second term the sum has to be taken over aLl (f,d) - clearly in Br and en der:end on i-;
the choice of the fj.'= , i € f , factors, j-f (i,d) is connected.
is
. Notice
space
{x=
wLth associated
for
neL_qhbours. A
N fo sone n €N.
vector
r ier
if
.i ,d.i i )
:
above are uniguely
A':=0"=
(x,1) =
*!
and wrlte
= 1 = tt... l1
....,
( frd)
case, we (di
(dii,dii)
connected,
I € f, 1n ii)
| = {1, ....r
Qf
-
d t.t l, = d , . ft ot r af lol ri , i a€ l l i , j € f lr c f . _. which are joindd by an edge, are called
valued graph
Br
€ f
i'j
i and j by an edge of value
or simply
€ N such that
fl
but are unique up to scalar
-2-
Eor k€I
let
= (k.)
k
€ 0f
definedby
k,
= o for
k I
I
€ f
and k* = 1.
1.1.1
Definition:
(trd)
a) Let
be one of
the
following
valued
sraPhs (lrl= n)' Arr: *o......a.1 1, 2 ) Brr:ffi......H
(2,1) C: n
o--O......H
\ )--......a---a
/ ? n=6
E.: o
E7'
? n=8
3r;
n=4
tt.
I
( 1, 2 ) '4'
(1,3) Gr: o---
4
Sn-t
n>4
örr-t
n> 5
örr-
t
( 1, 2 1
(2t1)
(2r1)
( 1. 2 ' , )
( 2, 1 1
(2t1)
.E---{-_o.....H
\
-7-n=7
E6
n=8
Ej
-/'
\
-4-
n=9
-8
n=5
x "41
n=5
-F 4 2
n=3
dr.,
n=3
"22
( f ,d)
Chen vre call
1.1.2
Lemma:
( f ,{)
Let
of the followlng
(rr,4r,,
i)
(i,j)
(r
ii)
Proof:
a
If
i,j
( | ,d) contains
one
dijdji
> 5 for a pair
x I
a triple
(i,j,k)
Euclldian
graph.
there are i,j
€ f.
Then
graphs as a subgraph:
€
ijk
d . . d . . -> 4 , rl lr.
Ä,,.,' or Ä,,r. thus F I
= 3 for
lä) ,
€ fxlxf
€ I with
(f1,d1),
Let i,j
,@w*h
= 2 for t r(resP.
= 3 and djrd*j
a subgraph of type for all
be Dynkin.
(resp. ( | i,gä)
urjuj,
iii)
not
.
:&+'i.h
€ f
2,9)
for
(graph)
Euclj.dian
. . i ! L W f L r r
I I u . . s . i i ' )
-J -
2 J .
( f ,d)
contains
a s s u m e d .r l . d .1 1 . -< 3 Because (f,d)
is
-t-
not
Dynkln,
i or j must have a nej_ghbour k € I
above dildkj
< 3. It
graph of type utjdjtg there
is
( tz,lzl
S t
a subgraph of type Et, all
{1,j}
with
€t
Ct or 60a,lrl
;
{k,f}
g I
F41 ot Fnr,
or it
must havg 6 branching
ls
of
type 0a
l,j
not Dynkln.
€ I
type Äa,
rrr
If
or !r,
because it
has only
branchlng point,
A bilinear vector
it
Leumas tet
varued graph
Proof:
(r,g).
Clearly
and take x'=
lt
Brr
(f',d')
is
the vector
it
a subgraph type agaJ-n because
lt
if
contalns
positive.
lrl
2 t €N.
if
O(I)
all
I
> o for
aII
€ en and positive definite.
the connected
then Brrispositivedefinite.
Assrxle B.
minimal hrith this
defined
E,
form o on the rational
a proper subgraph of
is
one branching
more then one
but not positlve
B, is positive,
ar1
a subgraph of type Er,
> o for
rf
a subgraph = 1 for
at reast
quadratic
g(x)
positive,
€ Of'
= 1 for
contaj,ns a subgraph of
is called. positive,
(f,d)
dttdtx
a subgraph of type ö,,
5 (xi) € QI' b" with er,(x,) z =(?t)
If
associated
(f',$')
contatns
contains
contalns
1t contains
contains
definite,
lf
it
not Dynkln.
space en, n €N,
senldeflnlte,
1.1.3
one,
form B wlth
€ 0n, positive
. rf
2. rf
( I,d)
Thus assurne drjdj,
a circle,
Otherwise
is
now
polnt,
( f,d)
case
t € N.
contalns
t €N.
I
Po1nt.
it
lf | :
( f,4)
If
thus.assume
, our graph must contaln
fn the latter
or döa,
a sub-
= 2, then t €N
By the
contains
withdlidir=
dXtdtt
I
it
I
Leti,j
, say j.
(f,{)
Er., or örr.
i,di'),
e r
{k,1}
I
( f
,
2foral1l,j 1s {i,j}
easy to see, that
is
not positive
property.
Let
= o. since for arbitrary by z., = iyrl
for
all
definite,
I
€ eI,
i € f,
-o-
always
satisfj-es
for
i
f
all is
Qr, (z) < er, (1)we can assume
€ f'.
In view of minimality
connected,
d., 'oJo I
there
o. oefine
d. ].'l o-o x+ *.. ro2'or
x
e ef Uy
l',
f'
all
xi
+ fi -o
-.
x?
-o
*i
for
dr.
f.
x.x.,
with
€ I,,
i
E
-Jo
Jo
a
Jo
'
di s f* x] lo lo
> o
I o. Because
and io € lr = *i
,a-oJo i€f
-
xi
= o othenrj.se.
and x.
Then Qf (x) = Qr, (I')
jo € f -
exists
= (*i)
of
that
= f., (x. d' .i f+ x., X+ roJo Jo r.o Jo Jo Jo
d. d. ro lo
i
39
x' ,2Lo
2
!
_r
' o 'i o * ?
=-
: = -rff#.
Proof
Thus skx = x + <xrk> b Furthermor" Let
be a connected
9)
I
qi,i>
e Qf, k,i
€ l,
by direct
calculation
(1)
- -2Yk *
(2) sr
"i =k si
I
= I
and either
= -2,
and
t x or
I "k = dik
€ N
for
i,k
L * k. We get the following from the definition ur* yjr
rä, +
= s. sk if
sk x < x.
i
if
+ dik
formulas
o, )k;
= dki
i
I k. easily
Bf,
hence for 1:
+ (.I,kr
and only
of
€ r,
+ 2yk > o hence
= O
(3) sr"ksi"kL-sksiI= (.1 ,i> (4) If "i
1) (.I,\>
d.* = d*. = 1 "k
I
"k
I
k +
+
i
i
then
= (
+ )i
"k"i"kI-si"kI=k - sk =i sk - i 1 = "j. "k "i "k I (5) From (3) we conclude easily: rf
sk I
f
yor
sil
I I,
only if dir = tri Define
"k "i
I
= 1.
Ru S Rf , -1
now
then
I
v € Z,
= "i
"k "i
if "k L
and
by
R_1,={-xeerlk€r} Ro,=ireErlk€r] Rv+1: = Rv U {skIlx Let v > O, I an I
s1ts>I},
€ Ru, x e Rv_1. Then, by definition
€ Ru_,|and some
O < x - I
€ Rv, k € f,
=
i,
i
€ f , such that
hence
> O.
* =
"i
!
v > O. of > I,
Rv, there i.e.
is
- 11 -
Let
i
f k € r
o t
sk x - x =
on \,, that trivj.al. of 1.
So 1et lf
by lnductlon induction
v:1.
= ( )k,
show now by induction v = o this
changes only
the
i-th
o.
Thus il.*
Next
we will
forsome
ls
and
by
trj.vial
LfI,
inplies
]="kI..y=l "f * dff i > k,
5 1
show again
I€f
is
component
:: 1 and drr
€ Rv_1. For v = O this
sk I
Nord
+.I,
kt
For
< I.
s* I
(2),
Then, by
I o.
yk I
o also
I
because
"if Because si
sk x < x.
I . L. We will "k 5 1 and d*, < 1, if x*
dif
Thusr
-
L
"k "i !> < O and
skl
"k "i this implies O > "i again by lnduction,
< O we conclude "i
"k
I
"i I
By induction -
f !-, thus
€ Ru_2. Furthermore
+ )
I = ( +
= ( o and
""'
sk1 x = kt,
.....
"*a_,
=
some 1 < t < lrl
is
"
x < o' By
""'
"*a "n., = ---.. hence x "o., "na
"*a_.,Ea.
Similar.
(with
The notation
pkt,
c € Wr) will
be kept throughout
1.2.6.
Lenma: Let
c = sk
.. ...
sk
^1
gkt
(f,9)
Proof:
< n,
have
is
N, cI
=
-u
by I.
the
is
1.2.4). Hence there
.
cr-*r,
,
roots
smallest
(I,d)
Then
r*r,
positive
all
n, a.ta
,:k
-9. -r 2. , . .
Because
saym€
Dynkin graph,lrl=
=K2"
of
transformatj.on
paper,
this
-a^.
c- IK_l
a list
be a
to a Coxeter
!*r,
-a" I ^r:^z^^n^ =*1 ,
'| < i
respect
€ Wf be a Coxeter transformation.
&., ,
is
there
of
integer
Dynkin, Thus for exists
(l,d)
where a.
such
t,hat.-1.-"i
c is
of
< m -
nn,
order
finite
O < x € Rr andy ' 1 < r
€ N,
1
mh E c" x h=l such that =
rre
-
r-'l
= pf O, 1 5 t,
"-t ES Dynkin type.
Prescribing,
the
calculation,
ä. (Lt)
(f,d)
px.)
) .'-Ä.;:-,
for
< n.
lernrna for
enough to prove
0 of
.-t
1 < t
see later in
(indicated
(sL
Oc, ("k.
< O for ä"(pt .-t )
Remark: l{e will
S3
then
= s, pL ^1 *i+1
-Dk-1 -
direct
pk.
n,
-1
By an easy tables
(
1 < t
) pr ^i " t- 1
prove
to
aIL
A vertex
respect
vertices 0 of
k1
(frd)
to i. €f
(t,d) .,
n, , which
is
kn of
said f
such
-
that
a sink
...
s. *i-1 is
is
k1
with
called
admissible admissible
and if
...,k'
k1,
l. 3 .1 .
(i) ii)
+
-
e
is
iii)
(iii)
(ii)
t
i
,
k,
It
sinks,
also
is
for
easy
sources, kr,
,..
to
show
connected
= {1,...,n}.
graph
Then the
\rith
following
cj-rcuj.ts
in
(t,d)
n of
inplj-es
n of n(i)
{1,...,n}
such that
< n(j).
: easy : Choose an admissible
n bY n (kr) :
It
is
= i'
i
easy to
sequence k1r...,k'
= 'l,...,n. see,
that
n(1),..,,n(n)
is
sequence.
alfows
an admissible
orientation
seguence for
sources.
j-s a permutation
(ii)
admissj.ble
(1.3.1
be defined
can also
no oriented
o +o
and define iii)
.....
admissible
There j
Proof:
are
o is
iii)
case k1 ,
equivalent.
There
ii)
respect
with
sinks).
be a valued
and let
are
i)
( f , d)
Let
fl,
statements
this
In
a sink
is
s. 0 = a. K1
I,erq!4.
orientation
(for
for
, and k.
1.
an admissible
sequence
.....
s, *r,
a
1 < n -
sequences
is
an admissible
that
-
to
sequence
Of course,
is
respect
1 < i
n, s. K1
|8 -
us,
to
sequence (f,d).
order of
f
sinks
i-n such a way that for
the
fj.xed
1,...,D
admissible
an
. k.l
to
_ 19 _
Note alsor if
k1,...k.
sequences for
the same admissible
C =
S,-
for
any pair
*r,
...
Ref erences:
sr_
*1
-
Srt
*r,
and kir...,k,
...
of vertices
't I I ] ,
t22l
Sr_r =
ki
i,j
are two adrnissible orientation
Cir
since
s. -i
e, then a---nd
s. -j
c-----ommuce
€ I which are not neighbours.
and [ 23 ]
Realizations
2
Chapter
S 1
K-realizations
2.1.1
Remark: Let K in
a
: =
Proof:
\J
'r (d.,dr) D is
i J
t' \ \.\
the
= t
(drd, )
= tr
dr)
tr(d)
= k+ o,
projection
. Then
€ K1.
the f
"r tp
HomK (
K-Linear.
by the
above property
O +
r
by tr
o and with
d€D
the
by
followed
cases, o + r
both
._HomK
of
DDD)
is
, it
t
(DMF, K)
by
easy
to
of
map is
. This
and'
an F-D-bimodule
is
K)
DMF,
of
HomD (
, f
must be injective, the
(DMF, K)
Thus let
DDD)
DMF, oDo)
see,
are
f
that
Thus Homo (
K-dimensions.
hence
as F-D-bimodule,
also
the
by
DMF, DDD)
Hom" (oM",
similar
and
surjective
bijective
therefore
HomK (DMF, K) as F-D-bimodule. Honk
dZ€D.
K1
tr:D*
D and
of
Hence, in
D onto
of
P 1691 tr+
HonD (DMF,
elements
of
projection
r
then
f inite,
Property.
all
equality
K hrith
homomorphism.
an bimodule
since
dt'
Otu,
19 €
for
K is
126]
Then define
: Horno (
course
is
for
desired
If
center
lsee
K1 on K'k k >t.
Again by
and (2.2.'l ) we get
E x t r ( t ; . . . s l * r l r . , s i . . . t l * r E . ) ! e * t 1( E r . s, i . . . s l * . , r . ) , Er., ti
...t1*,
Ft€ [ (M,s1+1...sn Q). rr
source. of course, 11 is not a direct
"k*1...s. s u m m a n do f s l
(2.2.i\ rherefore by (2.1 .6 b) ) din
r*+1 re
(x',
2.2.4
Proposition:
"*
...s|*f
It)
= o and rt
Let
X€
_ I
a)X=CC'xeP,whereP€
L (
is
injective.
M , 0 ) . Then
L
(M,Q)isprojective.
Ea
sl+1 !r)
s ; + 1 E r ) r=* r " n - f 1 . : = . . ; ; - . ; - " . ; ; - =
= ( s k ( d t usn; . . . Hence Extl
Q,k is a
"
=
-
Thus,
lf
1< t5i n,
39 -
X ls
lndecomposahle,
i.e.
c* I
1 < t o
(indecomposable),
if
x = c-r
Pr for
x = Cr I*
for
and 1 o,
13t
5n, and
then
nxtl
This
Proof:
= C-t 31, 12 or
X + O, then
extl ( c- x, x) ! b) rf
( M,Q )l I
L
(X, c+ x ) =
statements
Ft F. r .c c
as bimodule.
are straightforvtard
consequences
(2.2.3) and (2.2.5).
Let r:'O,
t (
M,
0) ) x = c-r
Pa (or
1 1t< n. Then the position
by : pos ({)
= n.r
+ t.
If
x is
cr ra ) with pos (X) is
a fi.nite
defined
direct
-41
of preprojective
sum
nodules
(or prelnjectl_ve)
[ ( lr,l, 0 ),
Xt €
preprojectlve
-
(resp.
then X will
preinjective)
indeconposable be called
also
and pos X is deflned
by pos (x) = max pos (Ii)
2.2.7LeIuta:
a) LetX,
Y€
Then Y ls preprojective €
I
of position
L ( M , A ), I
preinjecitve
of positlon
a) First
and Horn (!,
let
< p.
preinjective
of posltion
p,
< p.
X be indecomposable,
o< t o.
Changing
€ IN, q >r
x to
be inde-
Then by
(2'2'3)
vtecansuPPose
Therefore
(dj.n c+qx)a+o
Coxetertransformation Let
indecomposable
preprojective.
for
there
exists
q>k'
all
and
1 O and 1 o
C-I = q. Let
in
11 s 1n.
...s;_1ls)r+
tr.,t., ...
o, if
t"_., E")a+ o,
e€ {o,1}
in |
t> s, i.e.
if
, (c-ps)t=
t< s and
there
(C-egs)t+ O. By the remarks
such that
(2.1.3) and (2.2.1) Hom (par c-t!")+ o. Assume F - I' 3 " * o. with the remark in (2.2.'l) we get
r-1+ C '- "
t'!",+
Hom (x, c-(r-1* and therefore
o. NowX is i.njective (2.2.3\,
every epimorphic
every image of X in i.e.
e)n.=g-a-(r-1*t
indecomposabre. This implies a-(r+ by (2.2.3),
it*1)!"
thus in every case c
proceed with
hence
must be injective, "-(r-1* *,r"a be j.njective, because it is
'!"
C-(r-1+e
image of X (2.2.8),
t'E"
s instead
This shows finally
t considering
c*(r+n-1't"
'r"
= o. Now
neighbours
= O for all
of
s in
1< s1n.
b) Similar.
2.2.12 Corollary: and J=
( f,
b)
P=
c)
statements
1
some 1< s< n and vj.ce
d) o,
and e) 1< t-< n)
versa.
f
.
-45_
11.2.6)
shows, that
e) r a)
: Let
(f,
( f
a)
implies
e) .
, d) not be Dynkln. Then, by (1.1.2),
d) contalns a subgraph ( f,,
Euclldlan
or one of
the
following
(dt2,dzt (r1 ,91 ) = 1t -
r)
(12, 92) =1.
ii)
d.tZ dZ.t = 3
)
'3
(d12' d21)
whlch is
graphs:
wlrh d1
zdz.t25
(d23,d32)
. ,
.,
wirh
d32 = 2
and dra
(d12'd,1).
(13, g:
rir)
d'),
1 =',.
(dzy
dgz).,
r.
with
dtZ dZt = 3=d23 d32
Let Q'be
the restriction
be the restrictlon L (M there
"
1s a full 0')
(*, (e x) . =1 ' '
e
exact +
L ( M ,0
is
true
0').
clearly
L ( l/',
We will
1gi.-.j
) rr , , . o . =G l'1
0')
e and consider
L( M', 0').
inf,
otherwise
/o L
and similar
for morphisms.
L ( M' ,
as subcategory
show, that
modure, which for
(M,,
and
) by setting
otherlvise ,
).
d,)
( Ä{,,0,)
ernbedding
fori€r'
a preprojective this
( f',
ft A ) to
L(l{,0
X = (Xr,ror)€
Thus we omit of
( 1,, d'),
to
Q',) the rnodulecategory of
e: L(M',
for
(
of
of 0
is
O' )
L (M , e) contains
not preinjective.
Then, by d),
Assume
no preprojective
- 46 (M',
[
module ln
(l
be the Coxeter element of
, d) with
1 is a sink with projective
respect L'( lll',
in
F1 is not preinjective
resPect
to
and'
O
we can assume u = 1. Thus
ay changing orientation
u € f'.
Let c = sn...s.l
is preinjective.
0')
and
to
0
0')
and
in
L ( M ',
and F1 is
Q',
L( l\{ , 0 ) . By assumPtion, by
therefore,
0'),
(2.2.1O) Hom (Et, !) + O for infinite many nonisomorphic modules Y.€ L(l'l ', Q'), hence the same is true in L( M, 0 ) and F., is not preinjective by (2.2.10).
Therefore
Thus hre can assume ( f, the projective
that
= Ct Ia
assumeIt
by (2.2.3).
(1.2.7)
"-r1 given
all
in
the tables
(f
For x = (x.,, xr)€
formula
(s-(r'+1){,)), r foraU.
{o
for
i = 1,2,3').
di),
the Euclidian
graphs, that orj-entation
d1). Let l € f be a sink, c-1 =s1s2.
O2 we get
it
1)x., - d'rax., dt2x1-x2). is
(c-r(t))r>
easy to prove by induction, o for all
r > o,
that
hence c-r !
r:o.
Assume ( f,
d) = ( t 2 ' 42) wittr
(d23' d32) = (2,1\. source.
t
in Appendix C) .
'(1) = (( dztdt2-
Vtith this
, d) = ( f i,
(with the special
rio
d) = ( ft,
Assume(f,
Thus
we can choose a special orientation
we have seen for for
show
is not preinjective.
is enough to prove c-r
(1.2.8)
{ o
we will
d').
some r> O, 1< t< n. Then c-(r+1)1< O
for
(of course also, if
In
c
d) = ( f',
module Fl
Hence it As in
r:O.
Q
is not contained in J also for
P
Q).
l(M,
all
L (M ,0 ) again
in
Then
1€l
(d12'
d21) = (3 ' 1) aPd
beasinkand3€f
a-1 = - 1 s, s, and
bea
/o
-47(x) = (2xt * *2
c
xr, 3x1 * *2 - x3,2x, - x3),
I = (x1 t x2t x3) € e3. now it .
(c
-1
this
x)3 1t
O. Thus
Z ' = s-;r . . . s-]1 z + o . Consequently
(2.3.1)
yields
an exact
sesuence
-54-
O+4,-
sl- ... ^1
si,by -r
and,applying
(2.2.112
Z_ +1.
Comparison of Iast
q
exactness of s1 (i €r )
refr
-X
I
-
!'-Ek
the invoLved
dimension
the
shows that
thus we get the exact
homomorphism must be onto,
sequence
-L
9
If
preprojective,
Y is
-
o
-
we get
X +
I
L-
References:
Most of
$ 1 is
The Coxeter
functorshave
I.M,
valued for
and V.A.
celfand
all
graphs i.
algebraically 5 3 is
(f,
-.j
9.
been defined
Ponomarev in
[1]
vrithoriencation"l,
in
i), field
Ringel
done by C.M.
d)
closed
done by V.
simiJ.arly
where K.
the
I.N.
by
for
quivers
modulation
Rj-ngel in
t251.
Bernstein,
where d..
Furthermore
Dlab and C.M.
in
for [15].
(j-.e. = t
j.s given $ 2 see
= dli by an [11]
-
Chapter
fII
Graphs of
An abelian tion
category
series
A
A
and is
has only
objects, (il,o), if
for
then
of all
is
for
Artin
K',
K'
finite
to the
L(M'o)
denotes the category
type,
generated
exact
to
the
is
free x
assoy.
and if
A
modules over
an
so,
subcategorles
them .
l(M,n)
type,
embedding
one has to consider
also
of those which
L( M,0)
If
said to be of
if
in this
(f,d)
and only
(f,g)
again that
Our purpose in this q'peif
finite
and only
full
typs,
is
neither
tame (repre-
tvpe.
valued graph.
if
(representation)
modules over
finite
in-
K-realization
would be too special;
of
surn of
indecomposable
turo non commuting variables
Assume notr in the following
is of
direct
composi-
(representation)
exact
mod* Kcx,y>
equivalent
nor of wild
sentation)
unique
finite
a full
dirnensional
mod* Kr<x,y>
are representatj_on
is
definition
in addition to
has a finite
said to be of wild
example the category
isomorphic
of
said to be of
where
in
above, this
ring
object
isomorphisms)
there
finite
K'-algebra A
every
number of non isomorphi.c
is
-L(M,A),
over
tame tvpe
be again a valued graph with
sarne field
ciative (For
a finite
L(i,{,0)
mod* Kr<xry>
in which
is
(r,g)
Let
and of
an (up to
decomposable objects, if
finite
55 -
if
chapter (r,g)
is Euclj-dian.
cases more in detail.
is
is
a connected
to show that
L(M,n)
is Dynkin and of tame type
Furthermore we will
describe
-55-
s1
The representation
3.1.1
Theorem: Dynkin.
of Dvnkin graphs
L ( / l ,, ln )
Moreover
is
sable representations (f,g)
(f,d)
lndecomporoots
and the PosLtive
is not Dynkin, then, by
non-isomorphic
preprgective
non-isomorphic
preinjective
f (M,n)
therefore (f,g)
Let
L (M,0)
of
is
of
given by the dim function.
If
Proof:
between the
a bijection
is
there
(r,d)
if
and only
type lf
finite
of
qfldimX=x2o.
(M,0)
modules) in
c
the
is
set
of and
infinite' tyPe'
rePresentation
finite
x € L (M,0)
Let
the set of
(and equivalently
modules
cannot be of
be Dynkin,
Q-2.12)
be indecomposable'
Then
m-
haveorder
--,1
r . l l r f
hence I = o by c' under is invariant E crx € 0t r=O tt*1* ' o (1.2.1). Therefore there is an r > o with "t*' is projective' for some 1 < t < n = ltl crx ! 9t By (2.2.3)
Then
v :=
x=c-tBt
hence L{M,n)
is
is preprojective.
Again by Q.2.12)
L ( l ' ', lo )
preprojective,
nunber of non-isomorphj-c
a finite
module in
Thus every
preprojective.
has only
hence indecom-
posable modules. Now the second assertion
give
we will (f,d) of
will
now some applications
be Dynkin,
K
an infinite
by (1'2'5)'
follow
of
Q.3)
field
and
to Dynkin graphs. (M,o)
a
so let
K.realisation
(f,d) .
3.1.2 Proposition: in
L ( M ,o ) ,
Let
{t,-..,Ia
such that
and
Z
be indecomposable modules
-57-
J
dimZ= Then there
is
a sequence
o = Zo c 21 c tion
n
of
-..
3 x- T r ( t )
t !t-1
there
is
{k1,.
Proof:
Lt,
all
for
...
s kd_t S kd.
ld s 1d_t
, 1 < t < d.,
/2. / lkt
are indecomposable
d ='1,
assertion
the proposltion for
to € {t r...,dl
aLl natural ,
rrithout
dim Z - dim X1 = 1 indecomposable with Then, by
of root
is
system of Dynkin graphs says, as sum of roots, also
trivial.
numbers
O nX
e
Wl
for
weget k+i€
=,t.
-
(xr) € ef .
for xi"., ! f ' ' r. € ( d i m X) . The !,Ieyl group x
,*
factor
if
nE if
{-L g eFlcx
representation
.!. € Qr* i)
For
representation
every
belongs
61=-x1,6i=Xi+dikxk,
vector
{x e Qflc*
to
XX ,=
transformation,
defect
by
of
R (it{,a)
of
0f"
by the
eft
type
R (M,a) )
i.".
Or,
rr X€Q'-.
eQI'
space
we write an
and
(in
respect
of
A regurar
dimension
be denoted
with
basis
the
subcategory
vector
(Xi)
defi.nitions.
series
will
the
natural
x€0'
if
The full
Now consider
the
basic
homogeneous,
representations
wrlte
the
then
there
is
an epimor_
=
-64-
equation
be non homogeneous possessing
E € R(M,o)
Lenrma: Let
3.2.4
L>2
and
i)
c+rE :
o < r < r
c+rE,
and all
E
the
of
orbit Then
be 1'
c
transformation
under the Coxeter
dim E
in
the elements
the number of
Let
n.
an
non-
are mutualry
isomorphic,sirnpleregularnon-honogeneousrePresentatj.ons. nX = O
il)
for
and x7c+e.
x7E,
Extl (C+rE, x) = o
iii)
with
there
Because
only
I
- {,
Let
I
this
q
has to be simple
E g Nf,
din
= n (E) > o,
there
is
that
there
is
E + X,
which must be an j-somorphism, because
By (2.2.2) x I
E, I
nX
(O
implies
we can assume, that
7 C*E
and consider
obvious. by defi-
a monomorphism
nX ) O
simil-ar
is
thus,
nition,
regular;
implies,
the orbit
by (2.2.'t\,
Now i)
representation;
regular
thus
a monomorphisrn
E) = dim E
must be an lsomorphism.
be a simple
!'
elements) '
number of
a finite
of
of an equation for
hence
not homogeneous,
factors'
(as element
q
of
Now dim c+le = cr(S
therefore
iii)
factor
on composition
(CIearIy, because E € R(itl,a)'
n (c+In)
Because s - c+lg.
ii)
additive
so by definition
is
E'
by (1.2.1).
can contain i)
is
n
must be a monomorphj-sm E
regular. I > 2
and
) o,
nX
representations
simpre regular
all
for
must be an composition
R(M,a))
representations
si-mple regular
all
x7c*t*ln-
and
nE ) O
Because
there
= o
Extl (4,c+rs) x7c+rn
Proof:
for
x7c+r+1n-
xlc+rE, iv)
with
X,
representations
regular
sinple
all
I
is
XsC+E.
r = O.
Thus assume
an extension
simple
_ 55 _
-O.
O-I-3-E and
Z_ contains
Now
X7y,
E 3 Y lv)
hence
a subrepresentation
because
Z *E
nX = O,
By ii)
is
the
identity
isomorphic
I
XlE,hence
=nX+nE=nE
nZ
Xfly=O on
E,
to
)O E.
andso
i,e.
the
sequence
splits.
Similar.
Now given is
which
E,
an equation
orbit
of
of
possesses
C+rE.
dim E,
an equation 2 < l- (
If
-
is
!r
observe
the
cardinality
crn
that of
the
put
n Kercrl=KnOg
can be seen directly).
So let for
X € R(M,e).
each Euclidian
(M',4')
of
(M,n1
Now, our graph
proof
and for
defined
will
each
by the
consist ,,
(t)
non zero
,
of
considering,
a contraction components of
n
(t)
,
- 74 -
and in decornposing
R(X)
into
indecornposable representations
of
( M ', a ' ) . /+I n'-'X
that
Note,
i.e.
R(x) ,
(t)x
n of
restriction
are
the
positive that
composition similar, direct the
notation,
contraction F * F),
-
2*-l*
or
llorv if
n(1)
nt5)
contaj.ns rf
n
(1)*
N o \ , ra s i n
for of
a Dynkingraoh,
must
% is
thus
(3.1), that
occur
in
to
the
and these
show,
isomorphic
isomorphic
t
n(t)x the
nonhomogeneous
E(t).
to
c+E(t)
for
some
for
graph
1 -
R(X)
into
the
types
set
p < n).
if
A2 t
representations.
a generating
is
Ep+1)
g(1),
direct of
consider
(wj.th
2
the
the
realizatj-on
sum of direct
type the
there
(o,j),
indecomposable summands are
('l,o).
of
of
I,
T' (yo) )
must be a direct (2.2.1)
n(1)'
we see,
!
is
summand
additve
( 1 , . 1)
and
T'(y-ol
= g(1).
type
Evidently
(namely
must be a direct
because
surnnands v
there proof
o,
isomorphic
to
summand Vl that
and
n(1)u
E of
a o
Thus
( 1)
o
de-
tables.
the
an equation
= n(1)x,
a submodule
the
to
defined
Dynkin
type
a o,
natural
(1,'l).
dimension
those
is
The dimension
{O,1),
the
of
R(X).
is
and decompose
components
denotes
we will
s x
on1y,
to the
= o
T' (yo)
E(2)
(1,o)
n(1)'v
summand
no regular
is
the
dimension
di.agram.
T" (!t)
of
of
their
=
representations,
of
by
the
and
< o,
are
n
11) t)\ = {E'" LZ, E'-'
:
n(1)
of
we refer
There
by
(t)'
a realization
particular
V1
if
,
determined
n(t)x
course,
First,
for
is
R(x),
summand
determined
(M' , e' ) .
to
roots
of
Ar, (n > 2)
%
(t)
one
if
Ä . , . ,, Ä . , r :
(of
= n
(t)'R(x)
summands are
implies,
For
uniquely
(M'rQ')
Furthermore direct
n
is
x
.
type
(1,O).
-75-
+ im19n+1 = x1
imtQ2 module
Ft
would
(x =
be a direct
be regular
(3.2.2
sunmand of
type
(1,O),
preimage
of
fore
the
From this
it
i).
{E = IZ}
ConsiCer
the
dlmension (o' l),
types
(1'1)
must occur
would by
d.
(2,1).
type
hence
(2,'l) .
type
be surjective,
xt
of
set the
with
82.
summands of n x > o,
rf
n x
or
(2,1) .
cannot
be of
would
negative
I
R(I)
2.
of
%
The
(o,1)
type
has a direct must
1q2
(1,O).
X
*.
(.1,O),
are
isomorphic
and
E(2).
,(1,Z'l
As above,
type
Xp+l.
n = 2*-.1
R(X)
< o,
be not
defect
for
a summand
If
be
g+S(1).
!
equatj_on
diagramm
there_
cannot
an equation
(1,o)
T' (v1 )
be a module
is
n(2)
not
has a direct
tqp+1
T"(yj)
3 n.
Vl
If
under
that
direct
T,(yo)
of
sur]ective,
the
or
sununand v1
cannot
shorrs that
of
and
ipZ f
to
would
R(x)
easily,
contraction
X
hand,
a generating
is
and
I,
projective
the
other
thus i*tqz
othen"rj,se
summand of
on the
follows
The same argument Err
(xi,iaj).
So
Vl
to
C+E,
be
is
wour.d be not
of it
regular
(3.2.2).
and
Ecnt
similar
-
/ tl 8D,.,: {E*" = l,
to case
8..
EQl = Frr";
..Fn-2(l
l r" a s'enerarins "n
set
$tith
equations
The proof For
for
E(2)
= 2*-1*
n(l)
E(1)
is
conslder
the
similar
and to
contraction
=
I(2) gn.
case to
2n*-1*.
11,2)
1
O,
The type tive type
a summand (O,1)
defect, (1,1)
would
thus, by
% lead
because
(3.2.2').
of
type
(O,1)
to
a submodule
x
i.s regular,
or of y-
( . 1, t ) X
occurs.
of
posl_
must
be of
- 76 -
Therefore
=t.,
T'(Yo)
o
*o,..+Fp.,.
f.,_Z(
p+2,
ft
^n O +
the modul,e would
o *
...
be a submodule
woul-dn't
of
be regular
_
Fp...".-r(;
by
T,(Vo)
of n hence
,
(3.2.2).
oosirive
of
defecr
and
I,
X
p = 2 and
Therefore
t2l
r'(v^) = E' If
(
n I
O,
( 1 , o ).
of type
T"(Vl)
cDn:
is
to
= -2
n'-' Di--!
F2 ...
r,
p + n-1,
If and
X
is
a direct
then
not
Vl
summand
'o * o ... odo for
"p
the
defect
regular.
of p = n-'l
Hence
BDn
C^ <e
set
*
+n
^i .-t
with
/1\
= -l
nt"'
,
^^-^'der
'i-. r
P4
äö-F: F"FO*.F Inn
a generatj.ng *
have
-
3g+u(2).
f,in t , I' , !n ( 1 ) = 1 r .3 , !F ( 2 ) =
t)\
must
so r" (vl)
negative
r'(v1)
simil_ar
is
R(X)
1 < p < n-1.
some
and
then
tLhr reE
6-0 7 rn_2_ld
...
equations *
F:2* "^^:; id = E ,L "(3)= o,, 3
n(1)
-
. . . . tnr_ 2
O-O /
-1*-2*+3*
*
+n
cu vor nr Ltrraa9cL tr ivol l n
tLoU
tLhr reE udrioaygt dr ranm
the
dimension
orf u
tL-y'lhJ ca
^a3 -
'\
1
/ 2lz In
the
decomposition
direct nF
t.,ri+i-^\.
e! wrrLrrrgl;
rf and
n(l)x
> o,
T,(V^) !
summand vt
1
(using O
^
R(X),
of
summands are
.
O O, ö t,
O
the ^
natural
1
of type
rt I
n ( 1 ) : o,
nx
of
type
GzZt
1.
summand ru
to the Dynkin graph of
the contraction
in
M
tion
Direct
every Euclidian o
and orientation
there
Thus we can formulate
!([,1,n).
3.2.8 Theorem:
for
(r,il)
Let
the product of
H(M,0)
R(t) , d.""tibed
in
calculation
orientation and
ß.2.7) .
shows also:
h
exists
theorem.
graph with n.
uniserial
with
a generating
the following
be an Euclidian
rtt and admissible
(l,g)
graph
Then
K-modula-
R(M,o)
subcategories
is
- 83 -
3.2.9
Coro1lar: h
Let
n
the nunber of
be the number of vertices elements
representations.Then all .
slmple
glven
regular
by the
L "
a generating
in
OShS3
(f,d)
of
set
and
of regular
andthenumber
non homogeneous representations
I
of is
formula
L = n+h_2 The number
h
is
the graph
of If
0a
is
Ärrtn > l)
an orbit
representatlon
vrhere
Let
1-
independent
of
of
a simple
x € l(M,n).
sion type, if
the
length
or
regular of
of
in
the case
2. nonhomogeneous
C.,
then
0+.
T h e n I € l(M,a)
dim X € N.,
except
h = 1
when
under the action
denotes
O
otherwise
is
of continuous of discrete
dimen-
di.mension
type. 3.2.10 Corollar:
The mapping
between all
indecomposable
mension type and all Proof: Iar Ler
dirn : L(M,n1 - qf
By (3.2.1) representations {s(t) llsr
lr
(c,3)
for
map
u , 3
is
T(A')
is
Z J'
easy to see that
ß and
(h11,).
s o c T ( A ) = e -y J
.L (hrl,) L'
of course
X ----+
o
T(c,ß)
I O
t(4)/_^^ ' s o c -r,(^Ar , , = ( E -X S
and
a homomorphism then
T
r
is
exact,
T ( O , G G , O )= I ,
For the proof
of
(orcc,o)
ii)
property,then L(ix,Y])). in
i)
a is and
note that
projecti-ve.
the property in ii). If
so
to the whole of
construction
steps
L !j-:Ly,e,
O o
A = (V",W",ro), where
tations
(in
(f'...-.',
s
induces a c-linear
by resrricrion to soc T(A), rhis induces 3,", and we can go backwards, i.e. T is ful-L.
(the extensj-on of
and
gX__-_-_____)o
J'.I
I O. Obviousl-y
withS=I If
is
(f..,) Xr -r4
O
ü
JtT(a,B)
Wä
J ',lsisr *
"l
I
where
g : Wc -
over G):
----------> gZ------->
O-->T(A)
o ------)
(where
diagram
is
an exact
Lr,(rM"),
i.e.
furl
also
not monomorphic, is
ernbedding;
to represen_
trivial).
By
im T c l(tx,y]). (FF,O,O)
Therefore
u e [({X,y})
T
every
is
injective
erement of
in irn T
is indecomposable satisfying
In(FttO), must have this
a n d V 'ts^o^ c- ,ur i O X forsome J,L€N JiThis means that g c a n b e e m b e d d e di n o z. Now arrsocUIOy
can be reversed
and we get a preimage of
U."
-93-
Renark:
Of course
submodules
modulation f{(l{,a) glven
image of
T
can be deterroined
cNr
be an Euclidian
i{ and admissible
graph not of type
orientation
we can assume of course that in
radical
the tables. of
also
for
proper
or
i'
wlth
of Extl (x,y) .
(f,d)
Let now
the
Let
nf
Q. rn order is
ö
to investigate
one of the orientatlons
be the generatj_ng element of
rrith r resDect respect
Of
i.,.,
to
.Qa. Let r-a+
5
N-,
the
i F L^ the !L^ source -^a fF b. io
E. o
8
(t,d)
if
6
is
of
-7 E^
ö
type
4
-41 F.
'42 'l
G" n
3
G2z
and
,
n.t 1 Notice
that
restricted Ii
= tt,i
otherwise
to
f'.
is
otherwise
short
to
root
the maximal
First,
non negative
for
in
the
of
Now the Lermnafollows
is
by
rirhere di = o
,r^
investigatiän
a root
cases
of
=d
and
shows,
(f',d),
in
fact
Fery
Bn, CDn, Fn1 and GI r
root. I,I
€ Of'
components. This
For the notation
case by case.
f,
(1,,d,)
defined
rhen a direct
restricted
the maximal
a Dynkin graph
= (yi) €or
Let I
(4f = (.t,i)).
3.3.4 Lenrna: I
Proof:
= f
f\{io}
long
say gives
and short
easily
x 2 1, a partial roots
inspecting
if
x _ I
ordering
see for
has on
ef'
example [ 4 | .
the Euclidian
graphs
-
(M',o')
Define the K-realizatlon let
yr = (Yir
y
to
restriction
of
defined by
Yi = Yi
{i,i}cr'g
f
(l',d')
of
!r r where
tyPe
of dimension
Y = (Yrrrar)
(3.1 -1) . Let
l',
and
by restriction
be the up to isomorphism uniquely
e L(M',Q')
i9'r)
rePresentation
deternined
94-
is
L'
the
€ t(M,a)
= O, j(9i = j9r. tf "ro is an inand .t0t= o otherwise. Then of course ! i € f'
if
of
(M,O).
we will
appty
(3.3.3)
= X
injective,
decomposable representation In the
following
Notice
that
F.
-i-
and
I
is
with
because
L(M,n).
F,
, Ye
i
€lisasource
_I
o (2.1.3) .
3.3.5 Lemma: i) ii)
Hom(X,Y)= O = Hom(Y,I). =F
EndX=F. 10P
iii)
Ext'(x,Y)
= ^N-
and
aredi-visionrings-
EndY=G
except if
A..,
is a bimodule of type
( r , g ) l = or" .l n. dö rr.H .t" cNr ," "r .r n" Proof:
i)
factor
of
morphic ii)
Because
Of
!.
End Y 3 End v',
= Ei -o
In particular
image of course
= O, I Yi ^o
it
be a submodule or
an ePi-
Y.
End X = F,^ th"
t""oit
= F
a division
is
for
follows
g Fi for G ancl (2 .2.4) . In fact 'o r | jo a 0' must have the sarne length
iii)
as composition
c a n n o t occur
cannot
{ .,-
!
as
=
; iö*.j
d.,
J'o
y' € of
y;. r
Because
from (3.1.1) '
some j o e f ' ,
By i) and (2.1.4)
d i n ^, , E x r 1- ( x- , y ) = - n Il t x- , v- l
ring.
'.
(2.2.12)
where the root
-9s-
Inspectlng (f ,d)
every
is
= tt^
of
case it
type
iCrr, h"r"
I'
is
of
e Q'
of
gives
this
of
) = 1, therefore EndY=EndYr
Let
This
is
fir.,
T:
type
= ,ro, c'
and But
some O < r € N, therefore
is
the maxirnal
is
the unlque
w €
wn, implies
i.e.
dim,ON) = 1, and
d"=ir"a.
""
tells
us that
there
of course
T
is a furl
is described
(3.3.3
in
we can speak about
exact
is of the same type
rMc
ii).
Because all
modules of
if
A e g*(füC).
and only
if
Then
T(A)
is
A
is
of
continuous
of continuous
continuous
L = dln
ker
(f ,d) of
be not of
continuous
type
4
is
V, - dim ker or) 6örr. fh.r,
dimension
nf = x + I
that
Therefore
pF + (din
type
because
of continuous
if
of
is
of
and only
if
dimension
T
type.
in (3.3.3)
= dirn V".
rüC
(f ,d)
dimension
dimension
Let A = (V,W, q) . Then by the construction dtun ( T A ) = d t u n w c . d i r X rrith ! + L.din
Notice
1
j € fr
l,=w(i),
Proof:
is
I,
(f,d)
type.
type
A
length
except j_f
o
are Eucridian
3.3.6 ternma: Let
Let
if
=
dim(cN)
a rong root.
for
L*(FMG) -!(M,o).
graphs
di.mension
except
the knowredge ot tt"
tro
=F1 . Now f,t=4.fr,
GNF. AIso the funageof
involved
of
hence
11r,4,),
(3.3.3) cNFo. Then
enbedding as
is
Y' = C-rrF,
type
=
#c
as above).
11',g')
Dynkln graph.
simple long root
CNf
NF = 4. Now
now ln every case
6örr. H"."
Is of
= 2
dllr(NF)
,Jo
type
root
that
dln
(jo e f '
uth(Nr),/f*
of
follows
is type
type
dim V, = dim !tO.
not of if
and
4,
type
ftrr.
and onLy if
-
96-
ditn(TA) = dln
W - ( d l n _f + d f u o X ) = d l n W ^ . _nl-- , u
i.e.
lf
contlnuous
(fral)
f4
u.
Is of
iCrr.
fh.r,
type,
if
ls
flC
and only
of
dlmenslon
type
i.,,,
Let
type.
and
of
ls
A
d1n VF = 2 dim WG. But thls
if
and only type
be of
continuous
= dlm WC(+E Y + 2 dtn x) = dim wc.lr,
din(rA)
lf
ls
dimenslon to
equivalent
because here
9r = 2 x + YNotice
that
A€ I-*(E$G)
r(A) ls
€ t(M,o)
lndecomposable,
composable, 1f and only
lf
lndecomposable,
ls
because
resp.
A
End(A) 3 Sna(f(a))
lf
and only
are lnde-
T(A) is
lf
a local
ring.
3 . . 3 . 7L e m m a : T ( f l * ( E J , ! G ) 1c R ( M , n ) .
Proof: Recall in
the
R(M,a)
functor o(t)
there
- up to
+ 1
of
the
in orbits
(3.2.7).
A, direct
(see 2.1.7) extensions.
(1 < t s h)
0(t)
inspection
(o s r(t)
isomorphisms dlrnension
(in
sion ring
non homogeneous representations
regular
is a unigue representatlon
type
R(M,o)),
as composition factor '
slmple
dlvided
n.lt) ) e p(t) r, l
continuous lt
notion
Ct
= (' A l Jt), the
(3.3.6).
Obvious by
H is
and
uniquely with
B(t)
- regular
Then
nxt(e(t) rg(t) ) = i.e. !rHH,
a fu1l
exact
o(t)
subcategory of
closed
be
of
length
occurs just
L11e(t) i) [(M,0)
B(t)
rp.dule
ena(g(t) )
4
orbit
-
= A(t)
and cornposition
4(t)
ß.2.7).
in every
A{ + o. Let ao
determined
socle
E(t)
hrlth
every element of
i.e. of
shows that a+r(t)
< r*) c
under the coxeter
once
is a dlvi= 3(t) under
+
-97-
3.3.8
Theoren: T induces an equivalence. between (1) (h) A *. . .* e x f l ( M , 0 ) = : C ( r r , t , e. )
Proof :
We have to shobr T(H,t(F!Ic))= C(M,a). By (3.3.7), (3.3.6)
and (3'3'3
ii)
it
is
enough to show thatanindecornposabre
ä € R(M,a)
of continuous
if
and only
if
ls
J.somorphic to a dj.rect
dlrnZ ="=
contains
sum of
sum of .
let
copies
"! E fr
sabLe direct
direct
=o
q.
of
itri) ) , hence
hence Z, contains
some simple
I t s t < h),
so every
direct
with
as above,
E
Furthermore every
because jo
restricted
= a"(z) j e r
Z_ is of to
image of regular io
u.
defect W is
and
is
all
Let
zero.
i€r.
submodules of thj-s j-s true
Then
q
is
has negati.ve defect.
-
,o.
öc(l{) *j^
*
w,
c(M,n).
rn particular,
can be seen.
ac(Z/u) - - z. of
regurar,
non homogeneous module
z cannot be contained in q
for
be a indecompo-
E
non homogeneous. But then
regular
Z, but this
such that
19",9'),
ur=i,
forall
In particular
W1 * O, as easily
neishbour
an epimorphic
i.e.
summand of
ö"(u)
by
isomorphictoa
regular,
summands of
nto = O,1w = (W1,
e1a(t)
is
!-
(3.2.2).
defect
s'nmand of
,
. ttoiice that di.m U = J.I o n, = (nr)eqr, because dim z eN.nf.
Z e C(M,n). Because
indecomposabre
bour
z = (zt,iq:1
* = Ei
of
where
Z_ have non positive
ZrU
such that
".a € L(M,n)
,/u"L"
and
C(M,0),
"]
=o,iti
usz
g
of
U = (Ui,iüj)
andU,
isasource,
2, wltnJ=_:,
for
?
-otr^
direct
g
copies
modure
contaj_ned in
g =
a submodule
fQrio+jer
Because io
First
g-
dimension type is
(zil , anddefine
1ti=iei
all
flnhUC)
,nur, is
öc(L). ;r.;, -o
;",
< O. So there
is
O. Note that
!'
of
-o
*j
hence
= o w
is
by (3.2.2),
impossible
always a root
Ler
at
least
neigh_
= dim W
the Dynkin diagrarn
-
98 -
Nou we have to dlstlnguish
11',9').
cases:
several
/
BDrrr Drrr E5' E.7, Eg, F42 and G22.
a) Type
Here y'
dim u = z, - o - - oI
hence
are at most
zi -o
sumnands in
=,,
tro
rmPlies
- Tnis
that
of
g.
into
By maximality
of
I'
all
gher:e
a direct these equals
restrlcted
to
I'
Furthermore
the
first
dim U
Y, because
= 1r
ö"(io)
a decornposltion
modules.
to
must be isomorphic
Also
ac(U) = - z.
and
indecomposabele
sum of
Rr,.
the maximal root of
is
z. . vr. to ör, ana 6örr.
fr,
b) Type Again
is
I'
the maxlmal root
component of every
root
(w' = (wi) € Rf ,),
because
there
just
are
be isomorphic
Here
at most
is
to
and again
U' which
must
Y' € Rf,.
of
by maximality
!
y,
of
summands i.n a decomposition
,j
*.i = t
1, hence
din U - 21
+ O. llow
ri
-
vn-1 3 1
1, and
= 1, because only
ti-r
for
n-1
dim U = 2.,
= 1, hence
JO
JO
roots of
(f',d'),
1. All
first
component
d) Type Again
' I
U. But
*l'=
2. So lt'
all is
of
a decomposition
gSI
root
the maximal short
is
I'
jo = t
in
Rf,
g'n.
c) Type
t.i
in
Rr,.
in
< I'
(f',d').
of
v = (vr)
roots joined
t
are just
= 1, hence
,l_
Therefore
Rr,'
by an edge with
and there tl
Furthermore
")- O = ,1,
1o' Now summands therefore
Jo
which are greater than g'
and therefore
= L',
I'r
have
i.€.
asdesired. io.r. I'
is
the maximal short
.1 = 1, therefore
dim U = zl'
root
of
(f',d').
L. As above
*i
Furthermore = 1, hence there
are
I
-99-
just is
z, only
dlrect one root
has defect e) Type
surulands in greater
zero.
a decomposition
than
U. In
namely the naximal
I, W g y.
As above
of
R, r there root,
which
F4t. that
-Notice
every
root in Rf, greäter than has defect O, where
O + a e A, then !' of
=O}
U
[ UH =, H€ S H+S
a representation
+boer)r{"-le)=(a
to the kernel If
is
Let
homogeneous modules with
by (:.3.1).
H(FMF)
we will
dfun S = n.
with a^
and
3
1 _____-___>2 6, thls (frdr)
so let
we may also (M,O)
proves
be a proper
assume that
restricted
to
-
the
lemma in
(r,A)
subgraph of is
11"4')
of Euclidian
connected. i e f,,
l,et
11',4').
the second case. type.
(M"Q,)
Let
j € I\f,
be
be neighbours.
Conqider
pi € L( l,{', e, ) _c L( /t{,a) . of course (din pr) o, i * "-r so *i = (Qim a-t !i). is arbitrarily large, because = dirn p. -. p r ) dlm C-r *E, ö.(dim nf, where m denotes the order of
c
modulo the radical
By (2.2.4)
End (c-r
= Fi,
so "-r
polnts.
(note that and
Bi
or
di\
depending
= -eltc-t
!i,gj)
Exr(Fj,
c-r
= -"ltgl,
Ei)
on the orientation
respectj-vely.
pi,Fj)
o, and this
We consider
only
so we have to prove (din
,M)
the
dim
acts
"lA centrally K
is
the graph
assume in
(f,4):
to be infinite.
with
are arbitrarily F = Frr
!,Iith
we get a full
exact
representatj.on
a common subfield dj-m and
of
*G
type
of
realization
F and
= g < -.
G, whiihIn parti-
G.
For finite
must be rnodified
than the category
(a,b)
xr
we need some notation.
paragraph
this
now nothing
K
fi
case.
of wird
pM6, and dirn *F = f ( -, contained in the center of F
ments and proofs is
K
is
"i
= dii
first
on
$ 4 we wilr
[ (FMG)
t(rMc)
(dirn Mc) > S. First = b, dim MG = u,
Let
As in
noer' that
fj
dimensions
=extl(c-r pi,Fj) = ll,, and GNF rgc "j, enbedding [,r(FMc) 59. Therefore
Of course
induced
1. Thena>5,
K-codimensi.on
that
is
the F::-orbits
and only
Firstletb=
endornorphism of
= vrhr
v1F, and vrF induces
a subbimodule
u € U, then u'
of
are F-bimodules,
two automorphisms
Consider F\. : = hu € U', So
i.e.
o and
t
U O (v1 + vr)F
of F. S
f\..
- 113-
+vr)
h.(u+v,
=u'+
(v.,+vr)f,=u,
forcjlg o= r.
Similar
and consider
U O (v.,+vliro)
forcing
d = ho, hence
copies
of
f o r s c n r af , e r
l s i < a. Now Iet
forall
F < FMF. Then,
for
a certain
ho€
F,
fr e Fr
+ (v., + vrho)fi = u, + v.,ho + vrhoho
nono - hoho.
F = K'
was arbltrary, of
= u'
+ v., + vrho)
h.(u
=v.ho
h.v.
+v.rho +vrht
Therefore,
must be comnutative,
sorne one dlmensionar
because
and
F-F-bimodule.
ho.
is
FltF
a direct
proves
This
F sum
the
propositlon.
3.5-5
corollarv:
rf
ab > 5, then
t(Fl'rc)
is
of wird
representation
tyPe.
Proof:
F = G = K'
Tf
sum of
copies
proved in
is
of some one dimensional
(3.5.3).
In particular
F = G = K, because
if
fy the assumptions of induction
K
enbedding from some wird
4,8 i) ii)
and with
category if
e L(FMG) vrith the following
true,
it
N^ : = Extl(B,A). ro. l . 1
For, by induction, by (:.3.3) L(Fnc).
this
if
is
into
is
a direct
has been pro
f = S = 1, i.e. let
fMG
prove the corollary enough to find
a full
satis_ by exact
L(FMG). so we are finished
we find
two incongruous
components
properties:
L e t E n d o = F . l. E n d B = G . , , t h e n d i r n Let
Flb
on M. So
we will
Of course
(3.3.3),
is
centrally
ii).
and if
F-bimodule,
this
acts
(:.5.4
over max {f,g}.
by induction
a commutative field,
*F.,,
dim
*G.,
< max{f,g}.
T h e n d i n. . _ FrN .' > - 5 - ..
L ( c N ^ ) i s of wild representation type, and '1 "t t h e r e i s a f u l l e x a c t enbedding from t,r.,*n., ) into
114 -
-
L (X) , $rhere X
purpose consider
For this
componentsof dlrnension type infinite.
By changing
a > b, hence < -1,
sion
of
so
E
End E
then
is
X3
by induction serial
composition )(o
An factors
is
L(fl'tc) i.e.
t (X)
and
all
A'
rhar B.,
und
is
a subfield
bounded.
So we can choose
End -n A
(rxt11e-,A. ^'o "o ) )
din
3.5.6
This
proves
Theorem: orientation
o. Let
a K-realization i) ii)
of finite
non isomorphic
with
order < f
*(End L)
an uni-
downwards),
(3.5.4) . Let in
extension
components in
B(Brr,Ar,) = B(2 Io,n.
-2n,
5. Now set
satisfy
4
=
\, "o
B = B-, "o
the conditions
i)
and
and ii)
the corollary.
(r,d)
Let
n + 1
n
End -o' X , the K-dim'ension of
of
o End An = F.,, then A, B and Fl above.
number
are incongruous
B'
X3€X\ {X1,X2},
L (E!{G) . Proceeding
in
be a non trivial
n > 1. Furthermore
End -n A
(in L(X)),
E
(in this din
of type if
of tame type if
be a connected valued graph utith admissible K
be an infinite
(f,d).
Then
and only and only
if
if
field
and
(M,o)
be
L(M,tl) is (r,q) (f,9)
.
exten-
a non trivial
natural
length
of
ehe K-dimension of nxtl (En,An)
Because is
for
every
is
X
e X. Then
It,Iz
components
for
incongruous
By (3.5.4)
the socle of
In,In_j,...,X1,ä
I"
of
End X2. Furthermore if
of
choosen such
* t {L,...,In} -a bct'(Yn,Xo). Again
is
incongruous
in
Let
there exists
X2. Now X2
are
set
we can assume that
necessary,
max{fr9J = f.
we can construct
object
where
by
a subfield
and
E
if
hence, by (2.1.4)
X1
the
(see (2.1.7) ).
*o
orientation
f > g, L.e.
B(I1,I2)
is
is
a Dynkin graph,
is an Euclidian
graph,
4
- 115 -
and iii)
of wild
type,
Dynkln Finally 1.)
-of
graph
course
it
nor
fleld
and
is
a
graph.
remarks: the
L(M,o)
process in
whlch satisfy
K,NK,
i-s an extension
is
resurts
to the
case,
a K-reari-zation
comes in
(3.5.5)
of
where
same varued
of
----)
(3.5.3).
of
K, and we get
[(M,n).
of course, K,
a full
exact
Here an extension
embedding
field
of
K
play.
some words seem to be in $reen tame and wild
do this
gories
this
cation
of
in
order
categories.
some chance to crassify
all
some speciar
concerning
all
finitely
category
indecomposabre
embeclding.
11,...,rd
it
l_-_->
K-algebras. over
K, let
modL K
M,- e...O
L__j,
"
t{-
(lh
d+2-times 21
acts
as the
(d+2) x
rn fact
For wird
For let C
we
cate-
(d+2)-matrix
by € nod'i R)
R
be
be an
be a full
Define
T : M-
is
wourd suppose the classifi..
S : m o d * K1 . 1 , " 2 > _ _ - _ > C
T : modt .Rc-->
bet-
there
objects.
cases of bimodures.
dimensional
and
the distlnction
For tame categories
seems to be hopeless,
K-algebra generated by abelian
rnay lead to a bimodule
the condltions
fierd
mod* K' 1"1,"2>
where
neither
(f,d).
The induction
will
(f,d)
if
an Euclidian
i-s easy to extend
finlte
graph
3.)
and only
we urant to make some general
K is
2.)
if
exact
-
/"
11 "r=['1
9J":...
['
is
easy to
have in
o
";,
\o
It
fact
see that a full
T
exact
defines
In particular, is
R, so every ring
4.)
of
if
R
an object finite
For simplicity supposed that
isomorphism
dimensionaL
So we
K, then
over
endomorphism ring K-algebra
here only
i-nvolved
birnodules.
ing binodul.
embedding.
occurs
isomorphic
to
as endomorphisrn
in C.
over a common central involved
with
dimensional
we treated all
exact
c.
1s finite on C
sorne object
full
embeddi-nq
ST : mod't R deg p(t)
such that
cn (R.
even Posters of all
for
a polynomial rf
n is
degree
€ I has degree k < n,
Let
I
of degr..
= rr 1t2;+irr(t2).t,p(t)i=r1
than n in
smaller
all
prinitive
ideal
= t2-a,
ft)2-ft2(t2)t,
is
i
hence zero.
a polynomial of
is
hence zero-
I,
over
right C so
the annihilator
ideals
as polynomial
of
ideal R,z,
is
only
Thus either
even or
o + a€lR or p(t)
*iah
Artinian
= t or p(t)
a maximal is
€Rlt2l
Therefore
= (t2-a)(t2-ä)
ring,
r.rords,
other
Let p = p(t)R
of R [t2].
it
R. Then "/,
a simple */-.
of
are maximal.
of R. By the above p(t)
irreducible p(t)
- p(t)i
I,
eBtt2i=
t have non zero coefficients.
< R be a maximal
where P denotes
n in
than
"^"tf.t = ip(t)
even 2irr(t2)
dimensional
finite
consequentlY r., (t2),r2(t2)
n is odd, then 2rn (t2)=ip(t)+p(t)
odd poqters of
only
Let O < k < n-1 be maximal
- p(t)'t
center of R. consider ip(t) (i2=-1 ) . rf
Of course
t).
€I.
o < k < n-l.
arl
'
o + g(t)
Then tp(t)
hence c* € lR for
principal-
R is
I of
ideal
hre see easily,
ej-ther 9(t)
for
= t,
somea€c\lR'
or
-
t2 - a€R.
Let a € G and conslder tz-a
= (t-b) (t-c)
for
U+E = o and bc = -a. of
this
equations
same b,c
we see that
p(t)
= t.
and So = "/p
2.1
is
End* (So) = O.
p(t)
= t--a,
right
ideal
)
O < a €R.
tS")
p(t)
= t2-a,
o > a € R. Then (t2-a)
ideal
and
*rn
= (t2-a) (r2-ä),
a maximal'right simple
=
the -
R/o module.
overJR, and
by the
"/p
the
complex
R is
also rnaximal-
R/"-rnodule
The sinple ". Il.
a € 0\lR.
ideal
"P /Dn - m o d u l e .
So we can paranetrlze R-modules
- simple
determined
is
= n.
ena*
p(t)
over O
\,iä).Ris amaxi.mal
R/f and S. =
ring
ideal
dimensional
Then I = (t -
(2,2)-matrix
Sa has endomorphisrn ring 4.)
also maximal as right
R-module,.one
uniquely
'/o = Y!(2,F.), the
as right
is
over p = (t2-a)RcR,
D
part
cases:
a simple
with
and imaginary
O < a € n.
four
up to lsomorphisn
3.)
the real
Then P = p(t).R D
Assume
€ 0. Thi.s forces
Separating
Sd we have to distinguish 1.)
-
Ilt
Then r=(r2-a)R is
over p = p(t)R
R7, and S. = i"
. M(2,C) and End* (S") = C.
isomorphlsm
classes
of
the
simple
numbers a € iD, whose imaginary
j.s non-negative. Again with
(3.4.3)
we can describe
t-lul
(M =
ncn o na6)
Of course
this
can be interpreted
normal form problern of
(n,m)-matrj.x
now fl(M) and therefore
as solution palrs
of
the
(A,B) over {D
part
th"
- 152-
!,/ith
the
definition
followinq
and (A',
Br)
if
similar, (of
comnlex matrices
of
there
correct
But the
(A.B)
Call (P,Q) of
a pair
is
invertible
such that
size)
PAQ-I = Ai and pEO-1 = E', conjugated
sirnilarity:
d e n o t e s t h e complex
where E,E'
to B,Br resoectively.
matrix
interpretation
matrix
following
seems to b e m o r e
interesting. Note that There
CAC
is
all
= COE Ch
a natural
Hon6 (vn 6 for
O
vector
Now L(l,l) is
0-C-bimodule.
"t
Homn (r*Gnrw6) ) " Honn (vAoAh%.CA,
spaces VC, WC over
the categary
of
where g,
tp' : Vn O
if
are automorphisms
there
Ro'
isomorphism.
C*,
A
O
Ah.
O
(VC, .ryC,o) ,
- WC äre called
nAC
,
O .
triples
all
I{A)
equivalent
q of Vn and p of WC
such that
wc
vcoc%encc
I
I s8 1 0I1
lp I
J
vcoch
isomorphism
;"äT" notation Two
of
similarity
lR-Iinear
are calLed
q:VC'VCandP:Wn
(pt
if
wc
onoc
above this in
is
Horn* (Vn I
transformations
similar
.t
there -
exist
ü,ü'.
equivalent Co*, vc o
regular
WC suchthat
to
the
following
Homn(a0n' I{n)) C%
{
C-linear
:
HomC (ncc, wc) transformations
- 153 -
vcoah
"otn,(11cc,
I
I
I
I
I n"'' I
J
(ncc'P) Homc
J
ut
vc e ch.
wc)
Honn (*0n, wn)
conunutes. Identifylns lrith
the
vC o
resbdctLons
the
following
CalI
a real
of
normal
2)-blocks
has the
if
exlst
there
((2n,
2nl
and
real
nurnbers we get
forrnally
1 < I
cornplex if
< n) of
its
every
partition
into
form
tkt'
^*,
\-on. (2n,
(naturally)
on'\
( "*'
Ttro real
the
!{C)
problem:
form
(1 < k < h,
h0a,
Vn, WC to
(2m, 2n)-matrix
(k,l)-block (2,
and Homn
Cf*
2rn)-matrices formatly
bkl
€ R
)
A,Ar
complex
( 2 m , 2 m )) r n a t r i c e s
are
said
regular p,e
to be O-similar square
matrices
such that
PAQ-1 = g' With
other
words we consider
transforrnations
normal
forms
betereen complex vector
of
real
spaces \,ri.th respect
to complex similarity. By the
above it
i.nto matrix
remains
terms.
to
translate
the
results
for
t (M)
154 -
-
by (:.3.1)
Flrst, only
an (2n, 2m) matrix
n = m+l (preprojective
if
matrix),-
- or if
n = m+1, and dually
So, if
matrix)
one indeconposable
(2n,
if
or m = n+1 (preinjective just
is up to sinilarity
in these cases there
indecomposable matrix
can be indecomposable
one
m - n (honogeneous matrix).
m = n*11 we have to find
just
2m)-matrix.
Let
Eo=
(Ä:)
c,ß €R, and consider the
for
?)
"-=(S
(2(m+1), m)-matrix
IE
'
p-
=
\
'-.'.
i
P*
with
space
In that
order there
to
transformation
a
(n+1)-dimensional { v . ' | , v . ,i , v , v r i ,
. . rw6*1 , w,o.,1i} (i2
{w1,.
prove is
I
an lR-linear
V into
{ w . ,r w 1 i , w r t w r i , . .rv*},
I
I
.--
to lR-bases
respect
{v1,.
II
I\ o ".". '.''o
|
describes
C-vector
\
..
\\ ' " o l
Then
\
^u
'.'.
|
(over lR)
\
I rE ' , . ' . /
andEsB=(ä-l)
.rw6*1}
are
no non-trj-vial
c-vector '..,v*,v.i}
= -
of
an m-dimensional sPace W, and
1) , where
C-bases of
indecomposability
g of
P*,
decomposltion
v and w,
we have
respectively'
to
show
VC = Vö e Vö
,
- 155-
WC = Wö O Wf such that
tp decomposes into
gt.
W".
-
Vt
This
is
gt'
Wt,
Vtt +
:
trivial
for
m = 1r for
without
R-linear
loss
maps
of generality
V'
= V,
hence tp" = O, Wn =,OT'!VI O W"C = rp(-V)-O Wf,, where denotes
aWI
subspace of
'l For m > let
generated
,
the
least
C-vecror
indecomposable.
V be the O-subspace (ü = (O), if
m = 2),
of V generated
by
and fr be the O subspace of W
fhen 6 = el?
by w2,...,r^/m.
(by induction,
i.e.
tp(V) . But 6-[VJ- = WC, hence
W contalning
Wö = tOl and g is
u2,...,vm-.'
of p(v),
the O-closure
: V - fr is
indecomposable
m > 2 , a n d b y + _ h eO - d i r i r e n s i o n s , 1 f r n = 2 ) .
if
Now e(V) = e(V')+e(V"),e(V')5W',9(V',)etv" i.mpli-es O(V)= (p(v) n W') O [a(V) n W,']. Nore that lalgest
p(V).
C-subspace of
Let o = o1 + u,
ut € 9(V) nW', 12 €to(V)nW". Then ui and ui
= *1 * x'
with
€p(v) nwr,
t
fr is
rhe € fi c
A(V)
,
= u,,i + uri €ff , x2 €a(v) flwr'
Now'
W = Wr O lrl" and W', W" are O-subspaces of w, hence = x1 , uri
rli
= x, and u.,i,
Thls irnplies fr c the other that
(ffnw')
inclusion
is rl is
injectlve.
(finW"),
e
being
trivial.
in
fact
,p-1 tfi)
is
g-1
(ff) c v,.
p,
Ofcourse
(Vnv"). i.e.
the whole of v,
O (fifl!{,'),
has full e
By induction
rank,
(o-1 (fi)n v.), we nnay
fr c W'. Again by i-njectivity
Now e(v1),
e ff,
a(v*i)
the JR-subspace of V generated
{v,,vrr92ir...,vm-1rv*-1i,v*} ,p-1rfi1 is
o
(say) fr = finW',
of e we see that
so fi = (ffnw')
S o t p - l t f i l = ( , p - 1( f i ) n V ' )
and, as above, ? = tVnV') assume that
u r i € r p ( V ), h e n c e u 1 , u 2 € f r .
by
, so the G-closure q=lfil so y = e-1fi1
w = e T V fS W ' , i . e . v = v ' , w = w ' .
.
v,
,
of
- 156 -
t
Let
I.
= Pfr
I^
is
indecomposable.
(the
transposed
Next vre want to describe H (M), M = that
O
nOC
the elements
generate using simple 1.)
C%.
we get
=
It
C O C - OC C 6 = 1 @ 1 - i
U = (O,O,p) , tp : lI I M -
Corresponding we get
the
9.
a)
t S" O
+ S.
q O,
O-base
Sa is
a)
of
O < a €lR
to
real
choosen
as
of
Mu r correspondinq as
C-sDaces
to
(p.,
and
the
above):
( a = o):
"\ t -
\o < O or
by
JI.J1
vC = wC = S"
( ""=+ s
be calculated
t , o ( v ,o e . , ) - r o ( v , 6 e r ) ) . i
l*"
b)
}ln can
tv., ,v.,i.....o*,.r*i)
t o l , r . ,e e r ) + o ( v . , & e " ) )
matrices
(where
the lR-bases
"/
l
ß > O :
/.
1ln
I'
I'r--l
az1
\o
t
o
q
1
ß-o
1
I
O,
?
o
1/
ß\
I
/Er I
E\
oul
E1
I
of
158 -
g
To
c)
corresponds
o\ -,)
lt \" that
Notlce
from the all
of a)
left
and the
) := "Jt For
€ r ß : o,
€
by
)
(Note that
't
rf
Q : vc + wc
VC
and
respect
is
a
tp
to
mean b7 irreducible series
etc.
Using
(3.3.1)
uniserial and it.s
(Vö,wü)
pair
are
(9(vö) I !'fö
a subtransformation
of
.
I
matrices
two
map betlteen
Vö , wö
if
and if
respectively,
u € H(M)).
to
lR-linear
\.re say the
WC,
or
/
corresponds
"il
B > o
where either
u"u)
("''
_
\"-l
'.c
given
o:
d,
2)
ä.,
,/2-.....-p\ T. \ / '- p + 1 _ . . . . . . . . - n Q. (x) =
-
t ( x , - x r ) " , where
the
edges
-
i
< p < n+l
I
sumnation
runs
all
through
j
'" '''-t\r, 6---=' 1 ) , lfY
,/'
n -l
\1-1
""'-r'/''
A
"tI"..._,>" =
where riqht
given
N is
of
of
K=center
fixes f
lrl
f
E'-' F O -- . . . O
oo oo-....o
E'-'
to. -.. -o oo o o .- - . . o
o. -. -..o
o-. -. .oF oo o"':
"o
oo o... - -.o
10-....o 1
o o -- - . . o
o 11" "'1
o--.. -.o
o" ".ol oo
o...o-11
u...
- r.9
: oFo" "o
(1)
v f
o. " "'o 1t
FF'.."F
r
{1)
dim C-
o 1 0 .- . ' o oo o......o Z=
ni.,
the
F on
by a field
automorphism
c'
and
UF
"N action
o" ' :"o
F of
(vrhich F).
-184-
if
p
l>
l>
^ts'
ö
N
@NH
r9
e
oooo\ +++ lr'!
lr'l
lrt trt
@NH
e
El
e o
e o
rlt
El
o
e
nl
4
e
e
hc
rd
El
@
hl
o e o
e o
o
e
fd
(E qt
e rd
El . (E)P E--E
lo
El
9^
lkl
lI Ee tl ^le It vY IE l'
o |Il
rd
(E
o
B
IE
(,
El
o
e. o l-. hi9 Ox
"jF El:
E
e |{
rd 6
N
o
El r. r9 :-1 rl
UP -14
t1
eP EIY eEl T
l(E
e
o n lr'l
r{
o
I |
El
"l
e El
le IE
U
I I lo
EJ
lh t' I
o
I
PO
lo lH'
lP.
HP NP
IF (rts
H
N
FI
NN
IE
N
NP
UJN
Nts
N
NH
NN tsP
oPo
PO
POO
oH
n
r,l
PO
lr
. P
H
oPo
N
POO ll (!P
@N
tll NP
HP
otsH
P
POP
NH
NP
-L97-
-41
(L'2')
a -
"
1 -
c
$l)
= 3(2xr- *r)2 + (3xn- 2xr)2 + 2(2xr- 3xr)2 + 6(2*r- *1)2
llr
=1-
2_ 3-2-
trn=o
-a.c =1->1+1-+-4+-2 = F-
M
F -
F-
Fl -
F, wirh [Fl:F] = 2;
dim
c'Et"
o I
ooF1FlFl
FOF FeF FeP FloFl
-1
-1
.r
o 1
I
'1
FA
100-1
1
o 2;\t o T j. 2\1-
o10-1
0
r
C-
lll
E'-'
"+,(1) = A(2) c+ E(2)
.r
u
n
r
v
11210
101-2
t'
L
-z
r
(2)
o1111
=t^
a(1) =
(1)
2222r
I
^4 -oA
n
u
"(2)
'1
r
L
oo211
dim
'1
OFF
(1'1)Fl
( 1)
cr
w
- 1a a
a
0
-
-
lvö
F nr. (2,r)
3 _
4 _
1
olx)
= o(2xT
.r
=1-2-i-4-z;s=(il;
*r)2
+ l(2xs-
*12
5;
+ 2(3x2-
2xr)2 + (3xn- 4xr)2,.
\-/ ä"
=1-+1->-3